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{
 "id":["123"],
 "optionid_123":"98"
}

I have the id as a variable, but from that how can I get the optionid_*? I tried a few things, but nothing seems to work. The each is inside of the appropriate function and jsonid contains the correct value. Here is my attempt at accessing the value 98 which doesn't work:

$.each(data.id,function(){
    var jsonid = this;
    console.log( data.optionid_+jsonid ); // doesn't work
});

{
 "id":["123"],
 "optionid_123":"98"
}

I have the id as a variable, but from that how can I get the optionid_*? I tried a few things, but nothing seems to work. The each is inside of the appropriate function and jsonid contains the correct value. Here is my attempt at accessing the value 98 which doesn't work:

$.each(data.id,function(){
    var jsonid = this;
    console.log( data.optionid_+jsonid ); // doesn't work
});

• javascript
• jquery
• json

Share Improve this question Follow edited Jun 12, 2012 at 1:05 Paul 142k2828 gold badges284284 silver badges271271 bronze badges asked Jun 11, 2012 at 1:08 anotherdevanotherdev 10377 bronze badges

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2 Answers 2

Sorted by: Reset to default 9

You can use Bracket notation:

console.log( data['optionid_' + jsonid] );

I think your loop with data.id is not correct. That is

$.each(data.id, function() {..})

is incorrect.

For example if you data looks like following:

var data = [{
 "id":["123"],
 "optionid_123":"98"
},
{
 "id":["456"],
 "optionid_456":"99"
}];

Then you need to loop over data and get your required property.

$.each(data, function(index, val) {
  var jsonid = val.id[0]; // as val.id is array so you need [0] to get the value
  console.log(val['optionid_' + jsonid]); // bracket notation used
});

DEMO

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