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I have a problem to add JQuery in file this is my code:
<html>
<head>
<script src='.10.2/jquery.min.js'>
</script>
<script>
$(document).ready(function(){
$('#k1').click(function(){
$('#k2').animate({marginLeft:'-50px'});
$('#k3').animate({marginLeft:'-450px'});
$('#k4').animate({marginLeft:'-450'});
});
});
</script>
</head>
<body>
<div class='wrapper'>
<div class='mainKotak'>
<div class='wKotak'>
<div class='kotak' id='k1' ></div>
</div>
</div>
</div>
</body>
</html>
the code above is in
<?php
echo" ";
?>
the jquery isn't work , please someone help me because i'm newbie in jquery thanks
SOLVED i'm just use jQuery with external javascript
I have a problem to add JQuery in file this is my code:
<html>
<head>
<script src='http://ajax.googleapis./ajax/libs/jquery/1.10.2/jquery.min.js'>
</script>
<script>
$(document).ready(function(){
$('#k1').click(function(){
$('#k2').animate({marginLeft:'-50px'});
$('#k3').animate({marginLeft:'-450px'});
$('#k4').animate({marginLeft:'-450'});
});
});
</script>
</head>
<body>
<div class='wrapper'>
<div class='mainKotak'>
<div class='wKotak'>
<div class='kotak' id='k1' ></div>
</div>
</div>
</div>
</body>
</html>
the code above is in
<?php
echo" ";
?>
the jquery isn't work , please someone help me because i'm newbie in jquery thanks
SOLVED i'm just use jQuery with external javascript
Share Improve this question edited Oct 31, 2013 at 12:36 Mamen asked Oct 27, 2013 at 8:26 MamenMamen 1,4467 gold badges22 silver badges47 bronze badges 3- 1 what errors are you getting?! – mamdouh alramadan Commented Oct 27, 2013 at 8:32
- when the div clicked the jquery isn't work but if i copy that code into a html file is work normally – Mamen Commented Oct 27, 2013 at 8:34
- 1 Thank you for wanting to mark your question as solved. However, we don't edit questions to do that here - we tick answers. So, either tick one of the below answers, or make your own and tick that. Thanks! – halfer Commented Oct 27, 2013 at 9:45
3 Answers
Reset to default 3don't use echo like that. You can write anything outside <?php ... ?>, in simple HTML
If I'm understanding you correctly, you need to echo out that jquery code via php? You can do this easily by escaping out any double quotes or backslashes (" , \) with a backslash. Since your code doesn't appear to have either, you should be fine.
You may also find that because javascript is particular about line breaks sometimes, adding the white-space line break character to the end of your echo is beneficial: \n
e.g.
echo "<html>\n";
echo "<head>\n";
echo "<script src='http://ajax.googleapis./ajax/libs/jquery/1.10.2/jquery.min.js'>\n";
echo "</script>\n";
echo "<script>\n";
There is an online tool for easily wrapping raw HTML in php echo that may help you too: http://www.andrewdavidson./convert-html-to-php/
If it still doesn't work after doing that, you likely have a syntax error. Check the source of your php-generated code as well -- pare it to the code you've pasted above to ensure they match up.
@Sanjay's answer above also makes a lot more sense if you can do it that way instead. You can switch between php easily:
<?php
include"db.php";
if(!isset($_GET['page']))
{
header("location:index.php?page=home");
}
switch($_GET['page'])
{
case "home": $title = "TITLE WEB";
}
?>
<html>
<head>
<title><?php echo $titleVar; ?></title>
<link rel='stylesheet' href='css/style.css' type='text/css'>
<body>
...
<php echo "Other content"; ?>
</body>
</html>
You need to add quotes character (') on css attribute and write correctly
$('#k2').animate({marginLeft:'-50px'});
bee
$('#k2').animate({'margin-left':'-50px'});
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