javascript - if charAt equal to a list of characters - Stack Overflow

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I want something like the following in Javascript

if str.charAt(index) (is in the set of) {".", ",", "#", "$", ";", ":"}

Yes, I know this must be simple, but I can't seem to get the syntax right. What I have now is

theChar = str.charAt(i);
if ((theChar === '.') || (theChar === ',') || (theChar === ... )) {
  // do stuff
}

This works, but there must be a better way.

Edit: I did this, but not sure if it's GOOD or not:

var punc = {
    ".":true,
    ",":true,
    ";":true,
    ":":true
};

if (punc[str.charAt[index]) { ...

I want something like the following in Javascript

if str.charAt(index) (is in the set of) {".", ",", "#", "$", ";", ":"}

Yes, I know this must be simple, but I can't seem to get the syntax right. What I have now is

theChar = str.charAt(i);
if ((theChar === '.') || (theChar === ',') || (theChar === ... )) {
  // do stuff
}

This works, but there must be a better way.

Edit: I did this, but not sure if it's GOOD or not:

var punc = {
    ".":true,
    ",":true,
    ";":true,
    ":":true
};

if (punc[str.charAt[index]) { ...

• javascript
• charat

Share Improve this question Follow edited Jan 27, 2014 at 15:14 lbutlr asked Jan 27, 2014 at 14:57 lbutlrlbutlr 43477 silver badges2020 bronze badges 0

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2 Answers 2

Sorted by: Reset to default 5

Define an array with those chars and simply search in the array. One way to do that is the following:

var charsToSearch = [".", ",", "#", "$", ";", ":"];
var theChar = str.charAt(i); /* Wherever str and i es from */

if (charsToSearch.indexOf(theChar) != -1) {
    /* Code here, the char has been found. */
}

You can do it with a regular expression:

var theChar = str.charAt(i);
if (/[.,#$;:]/.test(theChar)) {
  // ...
}

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