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I have an asynchronous function that returns a promise. The operation should only be performed once. I want all callers of that function to get back the same Promise, but I don't want .catch()es of one caller to affect another caller. Can I clone a promise, or implement this in another way?

I have an asynchronous function that returns a promise. The operation should only be performed once. I want all callers of that function to get back the same Promise, but I don't want .catch()es of one caller to affect another caller. Can I clone a promise, or implement this in another way?

• javascript
• promise

Share Improve this question Follow asked May 6, 2016 at 2:31 apscienceapscience 7,2831111 gold badges5757 silver badges8989 bronze badges 1

• Possible duplicate of Memoization of promise-based function? – Bergi Commented May 6, 2016 at 2:37

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but I don't want .catch()es of one caller to affect another caller.

They never¹ do (unless you've chained the callbacks, which you don't).

I want all callers of that function to get back the same Promise

Just do it. Promises are immutable values².

Can I clone a promise?

If you really need³ a distinct object that will follow the original promise (fulfill when it fulfills or reject when it rejects), you can use the then method without arguments:

var clone = promise.then();
console.assert(clone !== promise);

_{1: Assuming you use a proper promise library. I think I can remember a case of a library (old jQuery?) where then callback results changed the state of the promise.
2: In their resolving behaviour, at least. Every promise is still just an object of course.
3: You don't. You really should not. I'm just answering the title question, but you should stop doing weird stuff.}

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