javascript - Youtube data api v3 - how to ask for only a part of snippet in playlists? - Stack Overflow

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When I fetch a list of videos from a playlist with the youtube data api v3 (with youtube.playlists.list), I can define a list of parts to retrieve with the parameter "parts" in order to minimize the data load.

The api states (several places) that asked for a property with child properties, it will include all children properties too. But I can't find anywhere how to restrict a request to a child property, without getting all other parts?

In specific, I am interested in a specific thumbnail, but not in ids, descriptions, titles, other thumbs. So how do I specify a (gran)child property, without getting all parent and sibling properties too?

This is what the request looks like:

gapi.client.request({
    'path': '/youtube/v3/playlistItems',
    'method': 'get',
    'params' : {
        'part' : 'id, snippet.thumbnails.default',
        'maxResults': numberOfItems,
        'playlistId': playlistId,
        'order': 'date'
    }
}).execute(function (jsonResp, rawResp) {
    // do the funky chicken dance
});

I have tried the following:

part : 'snippet.thumbnails.default',

part : 'snippet#thumbnails#default',

part : 'default'

Neither worked out.

But I might be barking up the wrong tree here? Is it too much hassle to break up snippet into parts? Should I just accept to fetch the entire snippet, and dig out the part of interest clientside?

Thanks in advance.

When I fetch a list of videos from a playlist with the youtube data api v3 (with youtube.playlists.list), I can define a list of parts to retrieve with the parameter "parts" in order to minimize the data load.

The api states (several places) that asked for a property with child properties, it will include all children properties too. But I can't find anywhere how to restrict a request to a child property, without getting all other parts?

In specific, I am interested in a specific thumbnail, but not in ids, descriptions, titles, other thumbs. So how do I specify a (gran)child property, without getting all parent and sibling properties too?

This is what the request looks like:

gapi.client.request({
    'path': '/youtube/v3/playlistItems',
    'method': 'get',
    'params' : {
        'part' : 'id, snippet.thumbnails.default',
        'maxResults': numberOfItems,
        'playlistId': playlistId,
        'order': 'date'
    }
}).execute(function (jsonResp, rawResp) {
    // do the funky chicken dance
});

I have tried the following:

part : 'snippet.thumbnails.default',

part : 'snippet#thumbnails#default',

part : 'default'

Neither worked out.

But I might be barking up the wrong tree here? Is it too much hassle to break up snippet into parts? Should I just accept to fetch the entire snippet, and dig out the part of interest clientside?

Thanks in advance.

• javascript
• youtube
• youtube-data-api

Share Improve this question Follow asked May 4, 2015 at 14:23 hassehasse 90322 gold badges1111 silver badges2424 bronze badges

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1 Answer 1

Sorted by: Reset to default 9

Use the fields parameter to specify which subset you want from the results:

gapi.client.request({
    'path': '/youtube/v3/playlistItems',
    'method': 'get',
    'params' : {
        'part' : 'id, snippet',
        'maxResults': numberOfItems,
        'playlistId': playlistId,
        'order': 'date',
        'fields': 'items(snippet/thumbnails/default)'
    }
}).execute(function (jsonResp, rawResp) {
    // do the funky chicken dance
});

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