jquery - JavaScript - this.update is not a function - Stack Overflow

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Recently i tried to use JavaScript OOP with jQuery, I wrote this code:

var beer = function(){};

$.extend(ntf.prototype, {
    types:{
        '.test':'test',
    },

    init:function() {
        $.each(this.types, function(key, value) {
            this.update(key, value);
        });
    },
    update:function(className, actionName) {
        $(className + ' .event').click(function() {
            $(this).parent().find('.pevent').load('navigate.php?do=create&action=' + actionName);
            alert("TEST");
        }).click();
    },
    pics:{
        add:function(element) {
            $.post("navigate.php?do=nav&action=pics", {
                name:$(element).data('name'),
            });
        }
    }
});
beer.prototype.init();

But, in the console it return this error: Uncaught TypeError: this.update is not a function.

How can i use JavaScript OOP with jQuery in better way, And how can i solve this problem?

Recently i tried to use JavaScript OOP with jQuery, I wrote this code:

var beer = function(){};

$.extend(ntf.prototype, {
    types:{
        '.test':'test',
    },

    init:function() {
        $.each(this.types, function(key, value) {
            this.update(key, value);
        });
    },
    update:function(className, actionName) {
        $(className + ' .event').click(function() {
            $(this).parent().find('.pevent').load('navigate.php?do=create&action=' + actionName);
            alert("TEST");
        }).click();
    },
    pics:{
        add:function(element) {
            $.post("navigate.php?do=nav&action=pics", {
                name:$(element).data('name'),
            });
        }
    }
});
beer.prototype.init();

But, in the console it return this error: Uncaught TypeError: this.update is not a function.

How can i use JavaScript OOP with jQuery in better way, And how can i solve this problem?

• javascript
• jquery
• oop

Share Improve this question Follow edited Jul 18, 2016 at 23:28 asked Jul 18, 2016 at 23:22 user6184150user6184150

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 3

This is the scope issue. Please notice that "this" is different before the "each" function call and inside the call.

You can use the scope by assigning it to a local variable i.e. "me" in this case.

 init:function() {
    var me = this;
        $.each(this.types, function(key, value) {
            me.update(key, value);
        });
    },

And if you want to see what is the difference between the scopes, just log both and check in the console.

Here first "this" is the global scope whereas the second one (inside the anonymous method) is the local scope.

 init:function() {
        console.log(this);
        $.each(this.types, function(key, value) {
            console.log(this);
        });
    },

You can refer this for more clarification on scope of this : http://javascriptplayground./blog/2012/04/javascript-variable-scope-this/

In addition to what @Ash said, I am a fan of bind

 init:function() {
   $.each(this.types, function(key, value) {
     this.update(key, value);
   }.bind(this);
 },

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