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I have a regexp that matches all ascii characters:

/^[\x00-\x7F]*$/

Now I need to exclude from this range the following characters: ', ". How do I do that?

I have a regexp that matches all ascii characters:

/^[\x00-\x7F]*$/

Now I need to exclude from this range the following characters: ', ". How do I do that?

• javascript
• regex

Share Improve this question Follow asked Feb 16, 2016 at 8:13 Max KoretskyiMax Koretskyi 106k6767 gold badges353353 silver badges515515 bronze badges 1

• You can refer to this link: stackoverflow./questions/1127739/… – Calyfs0 Commented Feb 16, 2016 at 8:18

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3 Answers 3

Sorted by: Reset to default 5

You can use negative lookahead for disallowed chars:

/^((?!['"])[\x00-\x7F])*$/

RegEx Demo

(?!['"]) is negative lookahead to disallow single/double quotes in your input.

You can exclude characters from a range by doing

/^(?![\.])[\x00-\x7F]*$/

prefixed it with (?![\.]) to exlude . from the regex match.

or in your scenario

/^(?!['"])[\x00-\x7F]*$/

Edit:

wrap the regex in braces to match it multiple times

/^((?!['"])[\x00-\x7F])*$/

The IMO by far simplest solution:

/^[\x00-\x21\x23-\x26\x28-\x7F]*$/

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