javascript - JSON Stringfy only a few properties - Stack Overflow

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I have this object:

{
    name: "",            
    email: "",
    phone: "",
    protocol: "",
    area: "",
    subject: "",
    message: "",
    validation: this.validator.valid()
}

I wanna convert it to JSON, but I do not want the validation property on it.

I've already tried the following:

const test = JSON.stringify(this.state);
delete test.validation;

Any other approach?

I have this object:

{
    name: "",            
    email: "",
    phone: "",
    protocol: "",
    area: "",
    subject: "",
    message: "",
    validation: this.validator.valid()
}

I wanna convert it to JSON, but I do not want the validation property on it.

I've already tried the following:

const test = JSON.stringify(this.state);
delete test.validation;

Any other approach?

• javascript
• json

Share Improve this question Follow edited Jul 21, 2019 at 19:22 Philipp 47511 gold badge44 silver badges1919 bronze badges asked May 10, 2019 at 16:39 Guilherme L. MoraesGuilherme L. Moraes 12233 silver badges1414 bronze badges 7

• you want to select which property to stringify? – Diagathe Josué Commented May 10, 2019 at 16:42
• Yeah, @Webwoman I've updated the question: look what've tried. It worked for me ;) – Guilherme L. Moraes Commented May 10, 2019 at 17:25
• Ok, @Yunnosch, im sorry. I'll do it – Guilherme L. Moraes Commented May 10, 2019 at 17:37
• No problem, well done now. – Yunnosch Commented May 10, 2019 at 18:42
• Possible duplicate of Excluding object properties while json-stringifying array object – Heretic Monkey Commented Jul 21, 2019 at 19:08

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4 Answers 4

Sorted by: Reset to default 9

JSON.stringify takes a replacer callback you can use. The replacer function takes a key k and the value v being stringified as parameters. Returning undefined will have the effect of not including the key in the final result:

state = {
    name: "",            
    email: "",
    phone: "",
    protocol: "",
    area: "",
    subject: "",
    message: "",
    validation: "some val"
}

const test = JSON.stringify(state, (k, v) => k != 'validation' ? v : undefined);

console.log(test)

Note: used like this it will remove the validation key from any child objects as well, which may or may not be what you want.

It will work.

const { validation, ...rest } = this.state;
JSON.stringify(rest);

UPDATE - I found a different solution

It's very simple, in fact. I've discovered the solution here. The following lines solved my problem:

const formSubmit = JSON.stringify(this.state, ['name', 'email', 'phone', 'protocol','area','subject', 'message']);

If you put an undefined, JSON.stringify will skip it:

const yourState = {
        name: "",            
        email: "",
        phone: "",
        protocol: "",
        area: "",
        subject: "",
        message: "",
        validation: true,
    }

const copy = {
  ...yourState,
  validation: undefined,
};
console.log(JSON.stringify(copy));

Also, you can not perform a delete from JSON.stringify because it is a string an not an object literal.

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