admin管理员组文章数量:1316680
I have a piece of code I'd like to execute periodically until all subscribers have unsubscribed.
// This function shall be called *once* per tick,
// no matter the quantity of subscriber.
function doSomething(val) {
console.log("doing something");
return val;
}
observable = Rx.Observable.timer(0, 1000).map(val => doSomething(val));
const first = observable.subscribe(val => console.log("first:", val));
const second = observable.subscribe(val => console.log("second:", val));
// After 1.5 seconds, stop first.
Rx.Observable.timer(1500).subscribe(_ => first.unsubscribe());
// After 2.5 seconds, stop second.
Rx.Observable.timer(2500).subscribe(_ => second.unsubscribe());
JSFiddle
My expected output would look like that:
doing something
first: 0
second: 0
doing something
first: 1
second: 1
doing something
second: 2
<nothing more>
However, the doSomething
function is called twice when the two observable are called. Here is the actual output:
doing something
first: 0
doing something
second: 0
doing something
first: 1
doing something
second: 1
doing something
second: 2
<nothing more>
Am I doing a design mistake? Is there a way to do this?
I have a piece of code I'd like to execute periodically until all subscribers have unsubscribed.
// This function shall be called *once* per tick,
// no matter the quantity of subscriber.
function doSomething(val) {
console.log("doing something");
return val;
}
observable = Rx.Observable.timer(0, 1000).map(val => doSomething(val));
const first = observable.subscribe(val => console.log("first:", val));
const second = observable.subscribe(val => console.log("second:", val));
// After 1.5 seconds, stop first.
Rx.Observable.timer(1500).subscribe(_ => first.unsubscribe());
// After 2.5 seconds, stop second.
Rx.Observable.timer(2500).subscribe(_ => second.unsubscribe());
JSFiddle
My expected output would look like that:
doing something
first: 0
second: 0
doing something
first: 1
second: 1
doing something
second: 2
<nothing more>
However, the doSomething
function is called twice when the two observable are called. Here is the actual output:
doing something
first: 0
doing something
second: 0
doing something
first: 1
doing something
second: 1
doing something
second: 2
<nothing more>
Am I doing a design mistake? Is there a way to do this?
Share Improve this question asked May 15, 2018 at 15:03 FunkySayuFunkySayu 8,10111 gold badges43 silver badges63 bronze badges2 Answers
Reset to default 10The behaviour you are seeing is correct. The observable returned by interval
is cold. That is, no timer is created until an observer subscribes and, when one does, the timer that's created is specifically for that subscription.
The behaviour you were expecting can be effected using the share
operator:
observable = Rx.Observable
.timer(0, 1000)
.map(val => doSomething(val))
.share();
The share
operator reference counts subscriptions and multicasts the source observable to multiple subscribers - so there will be only a single interval/timer, shared between the two subscribers.
For more information, you might find this article useful.
Live working example.
Then you need to use Subjects
. Plain Observables are unicast (it means each subscriber own an independent execution of the Observable
). That is way each observer get called all the chain of the execution you have.
observable = Rx.Observable.timer(0, 1000)
.map(val => doSomething(val));
map
is getting called for each observer.
Subjects are a special type of Observables that allow values to be multicast, that means you share a single line of execution of your Observable. This is a rxjs6, if you get lost with pipeable operators, please take a look here.
First of all, get the imports
,
import { Observable, Subject, timer } from 'rxjs';
import { map, share } from 'rxjs/operators';
Then you have,
const subject = new Subject();
const doSomething = val => {
console.log("doing something");
return val;
}
const observable = timer(0, 1000).pipe(
map(val => doSomething(val)),
).pipe(share());
const first = observable.subscribe(val => console.log("first:", val));
const second = observable.subscribe(val => console.log("second:", val));
const tercer = observable.subscribe(val => console.log("tercer:", val));
// After 1.5 seconds, stop first.
timer(1500).subscribe(_ => first.unsubscribe());
// After 2.5 seconds, stop second.
timer(2500).subscribe(_ => second.unsubscribe());
// After 2.5 seconds, stop second.
timer(2500).subscribe(_ => tercer.unsubscribe());
本文标签: javascriptObservable executing once with multiple subscriberStack Overflow
版权声明:本文标题:javascript - Observable executing once with multiple subscriber - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1742006256a2412014.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论