javascript - Browsers: console groups - Stack Overflow

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I have this code:

console.log('before');

console.groupCollapsed('main');
console.log('test1')
console.groupEnd();

console.groupCollapsed('main');
console.log('test2')
console.groupEnd();

console.groupCollapsed('main');
console.log('test2')
console.groupEnd();

console.log('after');

It adds 3 lines to browser logs.
The problem is logs are splitted into 3 different groups.
Is it possible to append logs to previous group if previous log message and the current one have same group names (main)?

So now output is:

before
> main
    test1
> main
    test2
> main
    test3
after

and I want this output:

before
> main
    test1
    test2
    test3
after

Update: Code is async. So I should close the groups after logging to prevent logging from outside the groups to groups.

I have this code:

console.log('before');

console.groupCollapsed('main');
console.log('test1')
console.groupEnd();

console.groupCollapsed('main');
console.log('test2')
console.groupEnd();

console.groupCollapsed('main');
console.log('test2')
console.groupEnd();

console.log('after');

It adds 3 lines to browser logs.
The problem is logs are splitted into 3 different groups.
Is it possible to append logs to previous group if previous log message and the current one have same group names (main)?

So now output is:

before
> main
    test1
> main
    test2
> main
    test3
after

and I want this output:

before
> main
    test1
    test2
    test3
after

Update: Code is async. So I should close the groups after logging to prevent logging from outside the groups to groups.

• javascript
• logging
• browser
• console

Share Improve this question Follow edited Feb 9, 2013 at 13:51 Dmitry asked Feb 9, 2013 at 13:40 DmitryDmitry 7,5631212 gold badges6161 silver badges8686 bronze badges 1

• 3 What about the obvious act of not using groupEnd before using console.log? Works like a charm. – Rob W Commented Feb 9, 2013 at 13:44

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 4

How about a custom logger class

function Logger(){
    var logs = [];
    var gname = "default";
    function group(name){
        gname = name
    }
    function log(){
        !!logs[gname] || (logs[gname] = []);
        logs[gname].push(Array.prototype.slice.call(arguments, 0));
    }
    function flush(){
      console.log(logs) // loop for groups or just output array
      logs=[]; // clear values
    }
    return {group:group,flush:flush,log:log}
}

Usage

var l = new Logger()
l.group('main1');
l.log('foo','bar','foobar')
l.log('foo-bar')

l.group('main2');
l.log('foo')
l.log('bar')

l.group('main1');
l.log('foo2bar')
l.log('bar2foo')

l.group('main3');
l.log('foo')
l.log('bar')

l.group('main1');
l.log('foo3')
l.log('bar3')

l.flush()

You don't have to reopen a new group unless you really want to create a new group. So once you open a group, whatever you log will be attached to that group until you close it.

So with your example it would be

console.log('before');

console.groupCollapsed('main');
console.log('test1');
console.log('test2');
console.log('test2');
console.groupEnd();

console.log('after');

It shouldn't bother you but it takes a bit of a time for the browser to log these in groups. Just an additional note.

You only can do that by not closing the group. You could use something like this:

var curGroup;
console.logInGroup = function(group, log) {
    if (curGroup != group) {
        console.groupEnd();
        console.groupCollapsed(curGroup = group);
    }
    console.log.apply(console, [].slice.call(arguments, 1));
};

console.log('before');
console.logInGroup('main', 'test1');
console.logInGroup('main', 'test2');
console.logInGroup('main', 'test2');
console.groupEnd();
console.log('after');

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