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I'm looking for an array formula that can count the number of years in each cell from a single column. Here's a link to a shared google sheet showing the input data in column E and the desired output from a formula.
example input:
[1992-1993]
the output would be - 2
[1995-1997]
the output would be - 3
(1995, 1996, 1997)
[1995, 1997]
the output would be - 2
[1992-1993, 1994-1996, 1997]
the output would be - 6
(1992, 1993, 1994, 1995, 1996, 1997)
Thank you!
I'm looking for an array formula that can count the number of years in each cell from a single column. Here's a link to a shared google sheet showing the input data in column E and the desired output from a formula.
https://docs.google/spreadsheets/d/1eL2CTScKB8DGFI7pFbYnEsgljyEOysrW1IpXJAXtrTc/edit?usp=sharing
example input:
[1992-1993]
the output would be - 2
[1995-1997]
the output would be - 3
(1995, 1996, 1997)
[1995, 1997]
the output would be - 2
[1992-1993, 1994-1996, 1997]
the output would be - 6
(1992, 1993, 1994, 1995, 1996, 1997)
Thank you!
Share Improve this question edited Jan 31 at 18:10 Patsytalk 1,1171 gold badge1 silver badge15 bronze badges asked Jan 31 at 5:05 MartyMarty 414 bronze badges 1- Make sure to provide input and expected output as plain text table in the question. Check my answer or other options to create a table easily, which are easy to copy/paste. Avoid sharing links like spreadsheets, which make the question useless for others or images, which are hard to copy. Also, note that your email address can also be accessed by the public, if you share Google files. – TheMaster Commented Jan 31 at 5:17
3 Answers
Reset to default 1You may try:
=map(E2:E,lambda(Σ,if(Σ="",,reduce(,split(Σ,", ",),lambda(a,c,a+rows(sequence(right(c,4)-left(c,4)+1,1,left(c,4))))))))
Try this alternative approach
=BYROW(E2:E, LAMBDA(cell,IF(cell<>"",SUM(ARRAYFORMULA(IF(REGEXMATCH(TEXT(SPLIT(cell, ", "), "0"), "-"),VALUE(RIGHT(SPLIT(cell, ", "), 4)) - VALUE(LEFT(SPLIT(cell, ", "),4)) + 1, 1))),"")))
Input data - Years | Desired output - counting the number of years | |
---|---|---|
1992-1993 | 2 | 2 |
1987, 1989, 1993-1994, 1996-1997, 1999-2002, 2004-2006, 2008-2009, 2011-2012 | 17 | 17 |
1981-1983 | 3 | 3 |
1981-1982 | 2 | 2 |
1983-1985, 1987, 1990-1991, 1994-1998, 2000-2002 | 14 | 14 |
1981-1982 | 2 | 2 |
1981 | 1 | 1 |
1982 | 1 | 1 |
1983 | 1 | 1 |
1975-1977 | 3 | 3 |
1977-1978 | 2 | 2 |
1978 | 1 | 1 |
1979 | 1 | 1 |
1976 | 1 | 1 |
1982 | 1 | 1 |
1980-1982 | 3 | 3 |
1980-1981, 1983 | 3 | 3 |
1981-1983 | 3 | 3 |
1980-1981, 1983 | 3 | 3 |
1981 | 1 | 1 |
1977, 1980 | 2 | 2 |
1978-1979 | 2 | 2 |
1978-1979 | 2 | 2 |
1980 | 1 | 1 |
1980-1982 | 3 | 3 |
1983 | 1 | 1 |
1981, 1983 | 2 | 2 |
1982-1983 | 2 | 2 |
2004-2005 | 2 | 2 |
1988-1989, 1993-1994, 1996, 1999, 2001, 2004-2006 | 10 | 10 |
1986-1987, 1989-1990, 1992-1993, 1995, 1997, 1999, 2001, 2003 | 11 | 11 |
1986-1987, 1996 | 3 | 3 |
1984 | 1 | 1 |
2000 | 1 | 1 |
2001-2003 | 3 | 3 |
1992-1995 | 4 | 4 |
1990-1993 | 4 | 4 |
1993 | 1 | 1 |
2000 | 1 | 1 |
2001-2003, 2005 | 4 | 4 |
1986-1987 | 2 | 2 |
1988-1990 | 3 | 3 |
1984, 1997 | 2 | 2 |
1996 | 1 | 1 |
1990, 1992-1995, 1997-1998, 2001 | 8 | 8 |
1986 | 1 | 1 |
1986 | 1 | 1 |
1985-1987, 1989, 1991, 1994, 1997 | 7 | 7 |
1983-1985 | 3 | 3 |
1990 | 1 | 1 |
1985 | 1 | 1 |
1988, 1990 | 2 | 2 |
1984, 1986 | 2 | 2 |
2002-2004 | 3 | 3 |
Here's another solution:
=MAP(E2:E, LAMBDA(x,
IF(x = "", ,
LET(
s, SPLIT(x, ", "),
SUMPRODUCT(RIGHT(s, 4) - LEFT(s, 4) + 1)
)
)
))
For each row, we are splitting by the comma, then for each value, we are subtracting the leftmost 4 digits from the rightmost 4 digits and adding 1, finally we are summing the results.
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