ajax - How to print JSON response in javascript - Stack Overflow

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I am able to make a Ajax request and getting response as well in form of JSON string, still alert box of JavaScript is not showing actual response text. I am new to ajax concept and dont know much.

Ajax-Call:-

Action triggered on dropdown
<select name="state" onchange="getOptions(this.value)">

Javascript Function called :-
function getOptions(state){
  AJAX.onreadystatechange = handler;
  AJAX.open("GET", "getData?id="+state);
  AJAX.send();
};

Response Firebug is showing

This is my code to fetch response and print.

function handler() {
  if(AJAX.readyState == 4 && AJAX.status == 200) {
    var json = eval('(' + AJAX.responseText +')');
    alert('Success. Result:' + json);
  }
  else if (AJAX.readyState == 4 && AJAX.status != 200) {
      alert('Something went wrong...');
  }
}

Every time its a success but i get output as

I am able to make a Ajax request and getting response as well in form of JSON string, still alert box of JavaScript is not showing actual response text. I am new to ajax concept and dont know much.

Ajax-Call:-

Action triggered on dropdown
<select name="state" onchange="getOptions(this.value)">

Javascript Function called :-
function getOptions(state){
  AJAX.onreadystatechange = handler;
  AJAX.open("GET", "getData?id="+state);
  AJAX.send();
};

Response Firebug is showing

This is my code to fetch response and print.

function handler() {
  if(AJAX.readyState == 4 && AJAX.status == 200) {
    var json = eval('(' + AJAX.responseText +')');
    alert('Success. Result:' + json);
  }
  else if (AJAX.readyState == 4 && AJAX.status != 200) {
      alert('Something went wrong...');
  }
}

Every time its a success but i get output as

• javascript
• ajax

Share Improve this question Follow edited Feb 19, 2015 at 8:54 dakab 5,9251010 gold badges4646 silver badges7070 bronze badges asked Feb 19, 2015 at 7:47 user2332505user2332505 64922 gold badges1010 silver badges2222 bronze badges 4

• do var res=JSON.parse(AJAX.responseText); alert(res.name)...It will alert Dehradun – Rakesh_Kumar Commented Feb 19, 2015 at 7:48
• i tried that also , still same result – user2332505 Commented Feb 19, 2015 at 7:49
• 1 It is an array. You need res[0]. But why not use jQuery if you tag the question jQuery? – mplungjan Commented Feb 19, 2015 at 7:51
• 1 Do something like res[0].name.. where res[0] is the first object in array got after JSON.parse(AJAX.responseText) – Rakesh_Kumar Commented Feb 19, 2015 at 7:52

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 1

You need to treat your response as JSON not as text.

Try this:

function handler() {
    if (AJAX.readyState == 4 && AJAX.status == 200) {
        var json = JSON.parse(AJAX.responseText), len = json.length, i = 0, txt = "";
        for (; i < len; i++) {
            if (txt) {
                txt += ", ";
            }
            txt += json[i].name;
        }
        alert('Success. Result:' + txt);
    } else if (AJAX.readyState == 4 && AJAX.status != 200) {
        alert('Something went wrong...');
    }
}

If you need to see the value as part of debugging the code, you should use console.log(AJAX) to inspect the value.

If you really need to display some message to the user, then reconsider showing the json result unformatted/filtered - that said you could iterate through all the objects properties and concenate theese in a string (like @Hiral shows).

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