javascript - How to get the difference of two string arrays? - Stack Overflow

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I want to get the exact difference between two string arrays.

const array1 = ['T','E','A','P','A','P','E','R'];
const array2 = ['T','A','P'];

Expected Output Array:

['E','A','P','E','R']

I have tried this method:

const output = array1.filter(char => array2.includes(char));

But that removes all instances of a character, like:

['E','E','R']

I'm a newbie, so could you guide me to the right direction?

I want to get the exact difference between two string arrays.

const array1 = ['T','E','A','P','A','P','E','R'];
const array2 = ['T','A','P'];

Expected Output Array:

['E','A','P','E','R']

I have tried this method:

const output = array1.filter(char => array2.includes(char));

But that removes all instances of a character, like:

['E','E','R']

I'm a newbie, so could you guide me to the right direction?

• javascript
• arrays
• string

Share Improve this question Follow asked Apr 20, 2019 at 13:14 FallcFallc 10511 gold badge11 silver badge88 bronze badges 5

• 2 Whats the result for ["A", "B"] ["B", "A"] ? – Jonas Wilms Commented Apr 20, 2019 at 13:16
• Should be an empty array. – Fallc Commented Apr 20, 2019 at 13:19
• Why? Whats the logic behind that? – Jonas Wilms Commented Apr 20, 2019 at 13:19
• I basically have a character array of words (array1). If the user types something in, the character gets added to a used character array. The user is only allowed to type the characters in array1 and if one gets used up, he can't type it in anymore. So I have to have an array with allowed characters, which I use for input control. – Fallc Commented Apr 20, 2019 at 13:25
• Possible duplicate of get difference between two arrays (including duplicates) – adiga Commented Apr 20, 2019 at 13:28

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 6

You could take a closure over the index for the second array and increment the index and remove this item from the result set.

var array1 = ['T', 'E', 'A', 'P', 'A', 'P', 'E', 'R'],
    array2 = ['T', 'A', 'P'],
    result = array1.filter((i => v => array2[i] !== v || !++i)(0));

console.log(result);

A different approach without a predefined order of array2.

var array1 = ['T', 'E', 'A', 'P', 'A', 'P', 'E', 'R'],
    array2 = ['T', 'A', 'P'],
    set2 = new Set(array2)
    result = array1.filter(v => !set2.delete(v));

console.log(result);

You could remove elements from allowed based on the input array:

 const allowed = ['T','E','A','P','A','P','E','R'];
 const input = ['T','A','P'];

 for(const char of input) {
   const pos = allowed.indexOf(char);
   if(pos === -1) {
     // char doesnt exist?
   } else {
     allowed.splice(pos, 1);
   }
 }

Then allowed will be your expected result at the end.

I think filter is not correct apparoch here. Because there are some elements repeadted. Use a simple for-loop. And remove the elements when you add it to result.

const array1 = ['T','E','A','P','A','P','E','R'];
const array2 = ['T','A','P'];
const copy = [...array2];

let res = [];
for(let i = 0;i<array1.length;i++){
  let index = copy.indexOf(array1[i]);
  if(index === -1){
    res.push(array1[i]);
  }
  else copy.splice(index,1);
  

}
console.log(res)

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