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I am trying to get an array from PHP and to manipulate it further using jQuery. In my PHP file i do echo json_encode($data)
and when i put an alert in my response in jQuery i get:
[
{
"CustomerID": "C43242421",
"UserID": "432421421",
"Customer": "rqewrqwreeqwr",
"Add1": "rqwerqwreqwrqwrqwr",
"Add2": " ",
"Add3": " ",
"Phone": "4131231",
"Fax": "532442141",
"Contact": "reqwrqwrw",
"Email": "gfdgdsg",
"PaymentTerm": null,
"Country": "3231",
"City": "111",
"Zip": " "
}
]
, wich is a valid json array. Now what i try to do further is get the pairs as key => value as i would in an associative array in php.
$.post("templates/test.php",
{data: query,
cond: $(this).text(),
action: 'select'
},
function(res) {
alert(res) //outputs what i pasted above
$.each($.parseJSON(res), function(key, value) {
alert(key + value);
//this outputs: 0[object Object]
});
Removing the $.parseJSON
in the above function gives me a invalid 'in' operand e on jquery.min.js(line 3)
in Firebug error log.Can you assist me with my troubles?
I am trying to get an array from PHP and to manipulate it further using jQuery. In my PHP file i do echo json_encode($data)
and when i put an alert in my response in jQuery i get:
[
{
"CustomerID": "C43242421",
"UserID": "432421421",
"Customer": "rqewrqwreeqwr",
"Add1": "rqwerqwreqwrqwrqwr",
"Add2": " ",
"Add3": " ",
"Phone": "4131231",
"Fax": "532442141",
"Contact": "reqwrqwrw",
"Email": "gfdgdsg",
"PaymentTerm": null,
"Country": "3231",
"City": "111",
"Zip": " "
}
]
, wich is a valid json array. Now what i try to do further is get the pairs as key => value as i would in an associative array in php.
$.post("templates/test.php",
{data: query,
cond: $(this).text(),
action: 'select'
},
function(res) {
alert(res) //outputs what i pasted above
$.each($.parseJSON(res), function(key, value) {
alert(key + value);
//this outputs: 0[object Object]
});
Removing the $.parseJSON
in the above function gives me a invalid 'in' operand e on jquery.min.js(line 3)
in Firebug error log.Can you assist me with my troubles?
-
1
That's an array
[]
containing one object{}
. You must access the first element of the arrayparseJSON(res)[0]
– Michael Berkowski Commented Mar 5, 2013 at 14:01
5 Answers
Reset to default 4Try:
var r = $.parseJSON(res);
$.each(r[0], function(key, value) {
alert(key + value);
});
The result of $.parseJSON(res)
is an array, containing a single element (an object). When you iterate over that array (using $.each
), value
represents the entire object that's stored at the current index of the array. You'll need to iterate over that object to output its properties:
$.each($.parseJSON(res)[0], function(key, value) {
alert(key + ' = ' + value);
});
If you have an array with multiple objects inside it, this more general code should output the key-value pairs for all of them:
$.each($.parseJSON(res), function(index, arrayObject) {
$.each(arrayObject, function(key, value) {
alert(key + ' = ' + value);
});
});
res = $.parseJSON(res);
for (var i = 0; l = res.length; i < l; i++) {
data = res[i];
customer = data.Customer;
}
You have there an Array of Objects. You can iterate through the array of objects just like the code above.
You can get some kind of object from json:
function parse_json(res)
{
try{
return eval('(' + response + ')');
}
catch(e){
// invalid json
}
}
Try this:
$.getJSON('your-json-string-file.php', function (data) {
$.each(data, function(key, val) {
alert(key +'=>'+ val)
});
});
Hope this will help you
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