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When I try to copy paragraphs form one doc to another I get unexpected error:

It is necessary to detach the element

What does it mean? What am I doing wrong?

function test_copy_paragrahps() {
  var final = 'final';
  var doc1 = get_doc('', final);
  var doc2 = create_doc_in_path('', final+'test');
  var body1 = doc1.getBody();
  var body2 = doc2.getBody();
  var par1 = body1.getParagraphs();
  for (var i=0;i<par1.length;i++) {
    body2.insertParagraph(i, par1[i]);
  }
}

here is video

P.S. You can not mention on get_doc and create_doc_in_path implementations. Both return Document object.

When I try to copy paragraphs form one doc to another I get unexpected error:

It is necessary to detach the element

What does it mean? What am I doing wrong?

function test_copy_paragrahps() {
  var final = 'final';
  var doc1 = get_doc('', final);
  var doc2 = create_doc_in_path('', final+'test');
  var body1 = doc1.getBody();
  var body2 = doc2.getBody();
  var par1 = body1.getParagraphs();
  for (var i=0;i<par1.length;i++) {
    body2.insertParagraph(i, par1[i]);
  }
}

here is video http://youtu.be/1WdCD5ATiYw

P.S. You can not mention on get_doc and create_doc_in_path implementations. Both return Document object.

  • javascript
  • google-apps-script
  • paragraphs
Share Improve this question edited Aug 24, 2014 at 19:07 Karen Fisher asked Aug 24, 2014 at 18:15 Karen FisherKaren Fisher 7771 gold badge9 silver badges26 bronze badges 0
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1 Answer 1

Reset to default 7

You attempted to insert a paragraph that already has a parent Body. You need to create a detached copy of the paragraph before you can insert it.

See this part of the documentation that mentions detaching a paragraph.

I believe this will fix the error:

function test_copy_paragrahps() {
  var final = 'final';
  var doc1 = get_doc('', final);
  var doc2 = create_doc_in_path('', final+'test');
  var body1 = doc1.getBody();
  var body2 = doc2.getBody();
  var par1 = body1.getParagraphs();
  for (var i=0;i<par1.length;i++) {
    body2.insertParagraph(i, par1[i].copy()); //--- copy()
  }
}

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