admin管理员组文章数量:1416323
I am trying automatically generate Verilog from VLSI stick diagrams for logical output validation. The problem I am running into is that in general, transistors in VLSI are symmetrical, but the Verilog switch-level primitives each have a problem.
- nmos/pmos: Strictly unidirectional; source and drain are fixed. In reality, source and drain can change sides depending on the circuit state; the body is not connected to the source. See the example circuit below, in which the source and drain of transistor C depend on the states of A and B.
- tranif1/tranif0: Activation only depends on the gate, but it should depend on the source as well (nmos should only transfer 0 and pmos should only transfer 1).
So I need to combine the bidirectional feature of tranif0/tranif1 with the source dependency of nmos/pmos.
Does anyone have any suggestions for a workaround that accomplishes this without causing issues? It needs to be generally applicable since this is for automatic code generation. The Verilog does not need to exactly represent the topology of the diagram as long as it correctly produces its output. I'm not interested in analog effects, voltage drop, etc - this is a purely logic-level simulation.
I am trying automatically generate Verilog from VLSI stick diagrams for logical output validation. The problem I am running into is that in general, transistors in VLSI are symmetrical, but the Verilog switch-level primitives each have a problem.
- nmos/pmos: Strictly unidirectional; source and drain are fixed. In reality, source and drain can change sides depending on the circuit state; the body is not connected to the source. See the example circuit below, in which the source and drain of transistor C depend on the states of A and B.
- tranif1/tranif0: Activation only depends on the gate, but it should depend on the source as well (nmos should only transfer 0 and pmos should only transfer 1).
So I need to combine the bidirectional feature of tranif0/tranif1 with the source dependency of nmos/pmos.
Does anyone have any suggestions for a workaround that accomplishes this without causing issues? It needs to be generally applicable since this is for automatic code generation. The Verilog does not need to exactly represent the topology of the diagram as long as it correctly produces its output. I'm not interested in analog effects, voltage drop, etc - this is a purely logic-level simulation.
Share Improve this question asked Feb 3 at 2:29 Nick O.Nick O. 1851 silver badge7 bronze badges2 Answers
Reset to default 1A solution I've seen is converting MOS primitives directly connected to VSS/VDD as unidirectional nmos/pmos gates and the rest as tran
gates. There may be more nuances using unidirectional gates when directly connected to other non-mos primitives like a buf gate.
I've come to the following solution for now, but I doubt I've covered all the edge cases. It just passes the few tests I've run so far. Handling "x" in a way that propagates well will probably be a challenge.
module ideal_nmos(
inout wire t1,
inout wire t2,
input wire gate
);
wire gate_active;
assign gate_active = (gate === 1'b1) ? 1'b1 : 1'b0;
assign t1 = (gate_active && (t2 === 1'b0)) ? 1'b0 : 1'bz;
assign t2 = (gate_active && (t1 === 1'b0)) ? 1'b0 : 1'bz;
endmodule
module ideal_pmos(
inout wire t1,
inout wire t2,
input wire gate
);
wire gate_active;
assign gate_active = (gate === 1'b0) ? 1'b1 : 1'b0;
assign t1 = (gate_active && (t2 === 1'b1)) ? 1'b1 : 1'bz;
assign t2 = (gate_active && (t1 === 1'b1)) ? 1'b1 : 1'bz;
endmodule
本文标签: Bidirectional simulation of nmospmos in VerilogStack Overflow
版权声明:本文标题:Bidirectional simulation of nmospmos in Verilog - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1745251538a2649851.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论