Firefox Javascript: Why does .all not work? - Stack Overflow

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In IE, I can go like:

var x = document.getElementById("header");

alert(x.all[0].tagName);

If I try that in Firefox, I get the error "all is undefined".

What is the Firefox equivalent of IE's .all property?

In IE, I can go like:

var x = document.getElementById("header");

alert(x.all[0].tagName);

If I try that in Firefox, I get the error "all is undefined".

What is the Firefox equivalent of IE's .all property?

• javascript
• firefox
• properties
• undefined

Share Improve this question Follow edited Jul 30, 2012 at 18:28 Rustam 1,93322 gold badges1616 silver badges3535 bronze badges asked Apr 14, 2011 at 16:12 oscilatingcretinoscilatingcretin 11k4141 gold badges128128 silver badges214214 bronze badges

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2 Answers 2

Sorted by: Reset to default 7

.all is a Microsoft-specific extension to the DOM, and is not supported by any other browsers (except Opera, I believe, who simulate it in order to improve patibility with sites written for IE).

You can use things like x.children and x.childNodes, or x.getElementById() and x.getElementsByTagName() to reference elements below the current one in the tree, depending on your usage. I suspect in this case x.children is what you're after.

all would be the name of an array. It is not a native javascript keyword.

You may want to look at childNodes instead.

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