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I am trying to remove BBCode with attributes and content between those tags. I'm using this regular expression that I got here from here. I also tried other regex I found on stackoverflow but they didn't work for me, just the one I copy here is the closest.
([[\/\!]*?[^\[\]]*?])
I added a .
before *?])
and it maches the text between the tags but also matches pokemon
and I don't want that.
**Regex**: ([[\/\!]*?[^\[\]].*?])
**Text**: I'm a pokemon master and I like
[TAG] this [/TAG] pokemon [TAG] and this [/TAG] text...
I use this web to test regex /
Can anyone help me?
Thanks in advance.
I am trying to remove BBCode with attributes and content between those tags. I'm using this regular expression that I got here from here. I also tried other regex I found on stackoverflow but they didn't work for me, just the one I copy here is the closest.
([[\/\!]*?[^\[\]]*?])
I added a .
before *?])
and it maches the text between the tags but also matches pokemon
and I don't want that.
**Regex**: ([[\/\!]*?[^\[\]].*?])
**Text**: I'm a pokemon master and I like
[TAG] this [/TAG] pokemon [TAG] and this [/TAG] text...
I use this web to test regex http://regexpal./
Can anyone help me?
Thanks in advance.
Share Improve this question edited May 23, 2017 at 10:34 CommunityBot 11 silver badge asked Aug 19, 2011 at 5:28 Jose AdrianJose Adrian 1,2371 gold badge17 silver badges32 bronze badges3 Answers
Reset to default 3str = str.replace(/\[(\w+)[^\]]*](.*?)\[\/\1]/g, '');
jsFiddle.
This is what you want:
.replace(/\[(\w+)[^\]]*](.*?)\[\/\1]/g, '$2');
JavaScript demo
Basically you catch the value between tags and then replace the whole string with that value.
Using a regex to do this isn't a very clean way of doing it though...
Sorry Alex but you didn;t read it seems.
This should do:
\[(\w+).*?\].*?\[/\1\]
This will look for a closing tag matching the opening tag - and also accept attributes on the opening tag. The JavaScript code should then be:
str = str.replace(/\[(\w+).*?\].*?\[\/\1\]/, "");
本文标签: Remove BBCode with Regex in JavascriptStack Overflow
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