admin管理员组文章数量:1415139
I am trying to integrate Razorpay in my application. Here is a code that controls loading of payment model when "Pay Now" button is clicked. I want to make the modal load on page load instead of button click. I tried submitting form via javascript to see if that loads the modal but that's not working.
Here is the code:
<form action="verify.php" method="POST" id="gateway">
<script
src=".js"
data-key="<?php echo $data['key']?>"
data-amount="<?php echo $data['amount']?>"
data-currency="INR"
data-name="<?php echo $data['name']?>"
data-image="<?php echo $data['image']?>"
data-description="<?php echo $data['description']?>"
data-prefill.name="<?php echo $data['prefill']['name']?>"
data-prefill.email="<?php echo $data['prefill']['email']?>"
data-prefill.contact="<?php echo $data['prefill']['contact']?>"
data-notes.shopping_order_id="3456"
data-order_id="<?php echo $data['order_id']?>"
<?php if ($displayCurrency !== 'INR') { ?> data-display_amount="<?php echo $data['display_amount']?>" <?php } ?>
<?php if ($displayCurrency !== 'INR') { ?> data-display_currency="<?php echo $data['display_currency']?>" <?php } ?>
>
document.getElementById("gateway").submit(); // Not working
</script>
<!-- Any extra fields to be submitted with the form but not sent to Razorpay -->
<input type="hidden" name="shopping_order_id" value="3456">
</form>
However, I also noticed that form actions to page verify.php
so if the form is submitted it will go to that page where I just want to load the payment modal. Hence, what I tried can just not be the solution.
I am trying to integrate Razorpay in my application. Here is a code that controls loading of payment model when "Pay Now" button is clicked. I want to make the modal load on page load instead of button click. I tried submitting form via javascript to see if that loads the modal but that's not working.
Here is the code:
<form action="verify.php" method="POST" id="gateway">
<script
src="https://checkout.razorpay./v1/checkout.js"
data-key="<?php echo $data['key']?>"
data-amount="<?php echo $data['amount']?>"
data-currency="INR"
data-name="<?php echo $data['name']?>"
data-image="<?php echo $data['image']?>"
data-description="<?php echo $data['description']?>"
data-prefill.name="<?php echo $data['prefill']['name']?>"
data-prefill.email="<?php echo $data['prefill']['email']?>"
data-prefill.contact="<?php echo $data['prefill']['contact']?>"
data-notes.shopping_order_id="3456"
data-order_id="<?php echo $data['order_id']?>"
<?php if ($displayCurrency !== 'INR') { ?> data-display_amount="<?php echo $data['display_amount']?>" <?php } ?>
<?php if ($displayCurrency !== 'INR') { ?> data-display_currency="<?php echo $data['display_currency']?>" <?php } ?>
>
document.getElementById("gateway").submit(); // Not working
</script>
<!-- Any extra fields to be submitted with the form but not sent to Razorpay -->
<input type="hidden" name="shopping_order_id" value="3456">
</form>
However, I also noticed that form actions to page verify.php
so if the form is submitted it will go to that page where I just want to load the payment modal. Hence, what I tried can just not be the solution.
3 Answers
Reset to default 3I found the solution. Posting as it may be of help for someone in the future:
In razorpay/checkout/automatic.php (or manual.php)
place this right after the opening <form>
element:
<script>
$(window).on('load', function() {
$('.razorpay-payment-button').click();
});
</script>
Attach an onload event to script and simulate click in the handler
<script>
function loadPaymentModal() {
const elem = document.getElementsByClassName('razorpay-payment-button')[0];
elem.click();
}
</script>
<form action="verify.php" method="POST" id="gateway">
<script onLoad="loadPaymentModal()" src="https://checkout.razorpay./v1/checkout.js"
data-key="<?php echo $data['key']?>"
data-amount="<?php echo $data['amount']?>"
data-currency="INR"
data-name="<?php echo $data['name']?>"
data-image="<?php echo $data['image']?>"
data-description="<?php echo $data['description']?>"
data-prefill.name="<?php echo $data['prefill']['name']?>"
data-prefill.email="<?php echo $data['prefill']['email']?>"
data-prefill.contact="<?php echo $data['prefill']['contact']?>"
data-notes.shopping_order_id="3456"
data-order_id="<?php echo $data['order_id']?>"
<?php if ($displayCurrency !=='INR' ) { ?> data - display_amount="<?php echo $data['display_amount']?>" <? php } ?>
<? php if ($displayCurrency !== 'INR') { ?> data - display_currency="<?php echo $data['display_currency']?>" <? php } ?>
>
</script>
<!-- Any extra fields to be submitted with the form but not sent to Razorpay -->
<input type="hidden" name="shopping_order_id" value="3456">
</form>
<script src="{{url('/')}}/frontendtheme/js/plugins/jquery-3.3.1.min.js"></script>
<script>
$(window).on('load', function() {
jQuery('#gateway').submit();
});
</script>
note: Use your min.js file folder on script source
本文标签: javascriptRazorPay form auto load on page load without clicking Pay Now buttonStack Overflow
版权声明:本文标题:javascript - RazorPay form auto load on page load without clicking Pay Now button - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1745205324a2647612.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论