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I have 6 images that load in different 6 different modal windows and they each have a next button and also a close button in them. The next button works with the following jquery code:
$('#nextModal12').click(function() {
$('#featuresModal1').modal('hide');
$('#featuresModal1').on('hidden.bs.modal', function () {
$('#featuresModal2').modal('show');
document.getElementById('#featuresModal1').style.display="none";
});
});
$('#nextModal23').click(function() {
$('#featuresModal2').modal('hide');
$('#featuresModal2').on('hidden.bs.modal', function () {
$('#featuresModal3').modal('show');
document.getElementById('#featuresModal2').style.display="none";
});
});
However, the problem is: Even when I close/hide the first modal ('#nextModal12') by clicking the CLOSE button instead of the next, the second modal appears.
I believe this is because the hidden.bs.modal function is picked up and called again even when I'm not clicking the next button. How do I prevent the script from picking up the hidden.bs.modal function indiscriminately?
I have 6 images that load in different 6 different modal windows and they each have a next button and also a close button in them. The next button works with the following jquery code:
$('#nextModal12').click(function() {
$('#featuresModal1').modal('hide');
$('#featuresModal1').on('hidden.bs.modal', function () {
$('#featuresModal2').modal('show');
document.getElementById('#featuresModal1').style.display="none";
});
});
$('#nextModal23').click(function() {
$('#featuresModal2').modal('hide');
$('#featuresModal2').on('hidden.bs.modal', function () {
$('#featuresModal3').modal('show');
document.getElementById('#featuresModal2').style.display="none";
});
});
However, the problem is: Even when I close/hide the first modal ('#nextModal12') by clicking the CLOSE button instead of the next, the second modal appears.
I believe this is because the hidden.bs.modal function is picked up and called again even when I'm not clicking the next button. How do I prevent the script from picking up the hidden.bs.modal function indiscriminately?
Share Improve this question asked Jan 6, 2015 at 5:49 clodalclodal 1,83523 silver badges36 bronze badges2 Answers
Reset to default 8Try use .one function instead of .on. When you use .on() your callback would be repeating again and again, beacuse you bind it again for each click;
$('#nextModal12').click(function() {
$('#featuresModal1').modal('hide');
$('#featuresModal1').one('hidden.bs.modal', function () {
$('#featuresModal2').modal('show');
});
});
$('#nextModal23').click(function() {
$('#featuresModal2').modal('hide');
$('#featuresModal2').one('hidden.bs.modal', function () {
$('#featuresModal3').modal('show');
});
});
Don't bind hidden.bs.modal
again and again on modal click, just bind it once like,
$('#nextModal12').click(function() {
$('#featuresModal1').modal('hide');
});
$('#featuresModal1').on('hidden.bs.modal', function () {
$('#featuresModal2').modal('show');
$(this).hide();// you can use hide function
});
$('#nextModal23').click(function() {
$('#featuresModal2').modal('hide');
});
$('#featuresModal2').on('hidden.bs.modal', function () {
$('#featuresModal3').modal('show');
$(this).hide();
});
Alternatively, you can try
$('#nextModal12').click(function() {
$('#featuresModal1').modal('hide'); // hide first
$('#featuresModal2').modal('show'); // show second
});
$('#nextModal23').click(function() {
$('#featuresModal2').modal('hide');
$('#featuresModal3').modal('show');
});
本文标签: javascriptBootstrap 3 Modal Event (HiddenBsModal) Keeps RepeatingStack Overflow
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