javascript - Ajax readyState always 1 - Stack Overflow

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I'm tying to do what seems like a simple ajax but can't get it to work. Here's my code:

var xmlHttpRequest;

function processRequest(){
 alert("process request called with " + xmlHttpRequest);
 if(xmlHttpRequest.readyState==4){
  alert("status = " + xmlHttpRequest.status);
  if(xmlHttpRequest.status == 200){    
     }
   } else {
    alert("process request no luck readyState = " + xmlHttpRequest.readyState);
   }
 alert("process request exiting");
}


function updateCount(customerID, productID) {

 xmlHttpRequest = init();

  function init(){

 if (window.XMLHttpRequest) {
               return new XMLHttpRequest();
        } else if (window.ActiveXObject) {
            return new ActiveXObject("Microsoft.XMLHTTP");
        } else {
         alert("Your browser does not support AJAX!");
        }
  }


 xmlHttpRequest.open("GET", url, true); 

 xmlHttpRequest.onreadystatechange = processRequest(); 
}

Like I said in the subject line, readyState is always 1. What am I doing wrong?

Thanks! Eddy

I'm tying to do what seems like a simple ajax but can't get it to work. Here's my code:

var xmlHttpRequest;

function processRequest(){
 alert("process request called with " + xmlHttpRequest);
 if(xmlHttpRequest.readyState==4){
  alert("status = " + xmlHttpRequest.status);
  if(xmlHttpRequest.status == 200){    
     }
   } else {
    alert("process request no luck readyState = " + xmlHttpRequest.readyState);
   }
 alert("process request exiting");
}


function updateCount(customerID, productID) {

 xmlHttpRequest = init();

  function init(){

 if (window.XMLHttpRequest) {
               return new XMLHttpRequest();
        } else if (window.ActiveXObject) {
            return new ActiveXObject("Microsoft.XMLHTTP");
        } else {
         alert("Your browser does not support AJAX!");
        }
  }


 xmlHttpRequest.open("GET", url, true); 

 xmlHttpRequest.onreadystatechange = processRequest(); 
}

Like I said in the subject line, readyState is always 1. What am I doing wrong?

Thanks! Eddy

• javascript
• ajax

Share Improve this question Follow edited Jun 22, 2010 at 16:18 jantimon 38.2k2323 gold badges126126 silver badges193193 bronze badges asked Jun 22, 2010 at 16:17 EddyEddy 3,7231616 gold badges6363 silver badges9191 bronze badges

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2 Answers 2

Sorted by: Reset to default 2

You are calling processRequest before you start your request.

xmlHttpRequest.onreadystatechange = processRequest();

is wrong and has to be

xmlHttpRequest.onreadystatechange = processRequest;

This will store a reference to your method instead of calling it directly.

As soon as the ready state changes, the xmlHttpRequest object trys to call this reference.

Add xmlHttpRequest.send(); after xmlHttpRequest.onreadystatechange = processRequest;.

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