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We need to run a Python code which will control the GPIO of Raspberry Pi 3 from within the JavaScript. (JavaScript is listening for changes on database and when changes are made, function gets triggered and it should run the Python Code.
(This code is not working, like the alert message will pop-up but the python code isn't running which otherwise should turn the LED on. What am i doing wrong?)
index.html file
function runPython()
{
$.ajax({
type: "POST",
url: "/home/pi/Desktop/Web/led.py",
data :{},
success: callbackFunc
});
}
function callbackFunc(response)
{
alert("working");
}
led.py file
import RPi.GPIO as GPIO
import timemGPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(18, GPIO.OUT)
print "LED on"
GPIO.output(18, GPIO.HIGH)
time.sleep(10)
print "LED off"
GPIO.output(18,GPIO.LOW)
We need to run a Python code which will control the GPIO of Raspberry Pi 3 from within the JavaScript. (JavaScript is listening for changes on database and when changes are made, function gets triggered and it should run the Python Code.
(This code is not working, like the alert message will pop-up but the python code isn't running which otherwise should turn the LED on. What am i doing wrong?)
index.html file
function runPython()
{
$.ajax({
type: "POST",
url: "/home/pi/Desktop/Web/led.py",
data :{},
success: callbackFunc
});
}
function callbackFunc(response)
{
alert("working");
}
led.py file
import RPi.GPIO as GPIO
import timemGPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(18, GPIO.OUT)
print "LED on"
GPIO.output(18, GPIO.HIGH)
time.sleep(10)
print "LED off"
GPIO.output(18,GPIO.LOW)
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edited Apr 20, 2018 at 5:54
DiLiP kUmAr
asked Apr 20, 2018 at 5:39
DiLiP kUmArDiLiP kUmAr
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- 2 Why is this tagged with PHP? – M. Eriksson Commented Apr 20, 2018 at 5:40
- 1 if this is possible through PHP? @Magnus Eriksson – DiLiP kUmAr Commented Apr 20, 2018 at 5:42
- 4 everything is possible if you put your mind to it – madalinivascu Commented Apr 20, 2018 at 5:43
- 1 1. Help you with what? You still haven't said what you actually want to do. 2. Both options (rewriting the code or set up your server) are too broad for SO. 3. SO isn't a substitute for doing research. SO is not a free coding service. – M. Eriksson Commented Apr 20, 2018 at 5:53
- 1 Ok. So. For a million security reasons, browsers will not let you run an arbitrary script on your puter, and certainly you can't POST an AJAX request to a real file outside the browser. You can, however, run a web server locally (that's listening to 127.0.0.1:SOMEPORT), post an AJAX request to that webserver, and that webserver can invoke the Python call. Someone remended Flask, that's a great super-simple webserver for Python and I remend it. – Ahmed Fasih Commented Apr 20, 2018 at 6:02
1 Answer
Reset to default 3You code is not working because you can't access and run script on server directly from a browser, you can only pass the data to the server using ajax
, therefore the url
in the ajax should be the server url, and you have to send the data
.
On your server (i.e. your Raspberry Pi), you need to have a http(web) server. The server will handle the post request ing from your javascript and control the GPIO accordingly. Like other mentioned, you can use Flask web development framework to create a web server for handling the request(s), or alternatively I often uses http.server which is part of python standard library to create my own GET and POST request handlers for simple applications like this one.
Here is an approach of using http.server
where do_GET
method create a web page and run the javascript when pointing the browser to the server/RPi IP/URL, and 'do_POST' method handle the post data sent by the ajax to control the GPIO.
web_gpio.py (in Python 3 syntax)
import time
import RPi.GPIO as GPIO
from http.server import BaseHTTPRequestHandler, HTTPServer
host_name = '192.168.0.115' # Change this to your Raspberry Pi IP address
host_port = 8000
class MyHandler(BaseHTTPRequestHandler):
"""
A special implementation of BaseHTTPRequestHander for reading data
from and control GPIO of a Raspberry Pi
"""
def do_HEAD(self):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers()
def _redirect(self, path):
self.send_response(303)
self.send_header('Content-type', 'text/html')
self.send_header('Location', path)
self.end_headers()
def do_GET(self):
html = '''
<html>
<body>
<p>this webpage turn on and then turn off LED after 2 seconds</p>
<script src="http://code.jquery./jquery-1.12.4.min.js"></script>
<script>
function setLED()
{{
$.ajax({
type: "POST",
url: "http://%s:%s",
data :"on",
success: function(response) {
alert("LED triggered")
}
});
}}
setLED();
</script>
</body>
</html>
'''
self.do_HEAD()
html=html % (self.server.server_name, self.server.server_port)
self.wfile.write(html.encode("utf-8"))
def do_POST(self):
# Get the post data
content_length = int(self.headers['Content-Length'])
post_data = self.rfile.read(content_length).decode("utf-8")
if post_data == "on":
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(18, GPIO.OUT)
GPIO.output(18, GPIO.HIGH)
time.sleep(2)
GPIO.output(18, GPIO.LOW)
self._redirect('/')
if __name__ == '__main__':
http_server = HTTPServer((host_name, host_port), MyHandler)
print("Running server on %s:%s" % (host_name, host_port))
http_server.serve_forever()
Run the python script on the server:
python3 web_gpio.py
Either launch your browser and point the browser to the server/RPi ip (in my example, it is 192.168.0.115:8000
) or run curl
mand form another terminal session to simulate the GET request.
curl http://192.168.0.115:8000
Hope this example would give you the idea on how to control something on your server using a simple web server.
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