javascript - how to add string with special character as json key? - Stack Overflow

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I want to add string with special character in JSON as KEY.For example "Sam@123"
Here is the code, that I am trying.

<script type="text/javascript">

var jsonObj={"sam":1,"rudolph":1,"js":1," ":12};
var key="samw@123";
alert("Add it.")
// Adding the key with Special Character in JSON
eval("jsonObj."+key+"=11")
alert("Added successfully.")

for(var i=0; i< Object.keys(jsonObj).length; i++){
alert("KEY#"+Object.keys(jsonObj)[i]);
}

</script>

I am getting following error at line 6 "eval......".

Uncaught SyntaxError: Unexpected token ILLEGAL

Is there any other way to add special character in Json as KEY?

I am also not able to add

var key="samw-123";

for this I am getting error saying

Uncaught ReferenceError: Invalid left-hand side in assignment

I want to add string with special character in JSON as KEY.For example "Sam@123"
Here is the code, that I am trying.

<script type="text/javascript">

var jsonObj={"sam":1,"rudolph":1,"js":1," ":12};
var key="samw@123";
alert("Add it.")
// Adding the key with Special Character in JSON
eval("jsonObj."+key+"=11")
alert("Added successfully.")

for(var i=0; i< Object.keys(jsonObj).length; i++){
alert("KEY#"+Object.keys(jsonObj)[i]);
}

</script>

I am getting following error at line 6 "eval......".

Uncaught SyntaxError: Unexpected token ILLEGAL

Is there any other way to add special character in Json as KEY?

I am also not able to add

var key="samw-123";

for this I am getting error saying

Uncaught ReferenceError: Invalid left-hand side in assignment

• javascript
• json
• special-characters

Share Improve this question Follow asked Oct 23, 2011 at 12:13 Ashish AgarwalAshish Agarwal 6,2831313 gold badges6161 silver badges9292 bronze badges 2

• 1 you don't need to use eval to do this, see wizard's answer below – wong2 Commented Oct 23, 2011 at 12:20
• 1 (a) You are not working with JSON here, only with JavaScript objects. (b) possible duplicate of Dynamic object property name – Felix Kling Commented Oct 23, 2011 at 12:52

Add a ment  | 

1 Answer 1

Sorted by: Reset to default 6

Should work fine using such syntax instead:

eval("jsonObj['" + key + "'] = 11");

Actually, eval is not even required:

jsonObj[key] = 11;

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