javascript - Regex for alphanumeric and special characters in jquery - Stack Overflow

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i tried to make a regex for my Address column the code is:

var str = "97sadf []#-.'";
var regx = /^[a-zA-z0-9\x|]|[|-|'|.]*$/;

if(str.match(regx))
   document.write('Correct!');
else
    document.write('Incorrect!');

the special character i want that is ][#-. the given code return me the correct match but if i add another kind of the special character like @% then the correct result i got, but i want the incorrect result.

i don't know where i did wrong please help me to make right..

EDIT: Sorry guys but the one thing i have to discuss with you that is there is no necessary to enter the special characters that i mentioned ][#-., but if the someone enter other then the given special character then should return the incorrect.

i tried to make a regex for my Address column the code is:

var str = "97sadf []#-.'";
var regx = /^[a-zA-z0-9\x|]|[|-|'|.]*$/;

if(str.match(regx))
   document.write('Correct!');
else
    document.write('Incorrect!');

the special character i want that is ][#-. the given code return me the correct match but if i add another kind of the special character like @% then the correct result i got, but i want the incorrect result.

i don't know where i did wrong please help me to make right..

EDIT: Sorry guys but the one thing i have to discuss with you that is there is no necessary to enter the special characters that i mentioned ][#-., but if the someone enter other then the given special character then should return the incorrect.

• javascript
• jquery
• regex

Share Improve this question Follow edited Dec 7, 2011 at 6:07 jogesh_pi asked Dec 7, 2011 at 5:54 jogesh_pijogesh_pi 9,78255 gold badges3838 silver badges6565 bronze badges

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1 Answer 1

Sorted by: Reset to default 3

The correct regex (assuming you want uppercase letters, lowercase letters, numbers, spaces and special characters [].-#') is:

var regx = /^[a-zA-Z0-9\s\[\]\.\-#']*$/

There are a couple things breaking your code.

First, [, ], - and . have special meaning, and must be escaped (prefixed with \).

\x checks for line breaks, where we want spaces (\s).

Next, lets look at the structure; for simplicity's sake, lets simplify to ^[abc]|[def]*$. (abc and def being your two blocks of character types). Since the * is attached to the second block, it is saying one instance of [abc] or any number of [def].

Finally, we don't need | inside of brackets, becuase they already mean one character contained within them (already behaves like an or).

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