admin管理员组文章数量:1389975
I want to load data from this url: /?s=aaa using Javascript.
This url returns data in my browser as shown below:
Here is the code I tried:
<html>
<head>
<title>The jQuery Example</title>
<script type = "text/javascript" src = ".1.3/jquery.min.js"></script>
</head>
<body>
<div id= "stage"></div>
<script type = "text/javascript" language = "javascript">
var url = "/?s=aaa"
$.ajax({
url: url,
cache: false,
method: "GET",
})
.done(function( html ) {
$( "#stage" ).append( html );
});
</script>
</body>
</html>
But I am getting this Error:
XMLHttpRequest cannot load /?s=aaa&_=1465298988417. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'null' is therefore not allowed access.
I want to load data from this url: http://gateway.fpts..vn/monitor/realtime/?s=aaa using Javascript.
This url returns data in my browser as shown below:
Here is the code I tried:
<html>
<head>
<title>The jQuery Example</title>
<script type = "text/javascript" src = "http://ajax.googleapis./ajax/libs/jquery/2.1.3/jquery.min.js"></script>
</head>
<body>
<div id= "stage"></div>
<script type = "text/javascript" language = "javascript">
var url = "http://gateway.fpts..vn/monitor/realtime/?s=aaa"
$.ajax({
url: url,
cache: false,
method: "GET",
})
.done(function( html ) {
$( "#stage" ).append( html );
});
</script>
</body>
</html>
But I am getting this Error:
Share Improve this question edited Jun 7, 2016 at 16:38 Kara 6,22616 gold badges53 silver badges58 bronze badges asked Jun 7, 2016 at 11:18 Ta No BiTa No Bi 3632 gold badges7 silver badges15 bronze badges 1XMLHttpRequest cannot load http://gateway.fpts..vn/monitor/realtime/?s=aaa&_=1465298988417. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'null' is therefore not allowed access.
- 2 Read about jQuery.ajax() here api.jquery./jquery.ajax. – void Commented Jun 7, 2016 at 11:19
5 Answers
Reset to default 2You are making a cross-origin http request as you are requesting data from a domain http://gateway.fpts..vn
which is different form that of your html file shown in question, say it http://www.requesting-server.
To allow cross-origin resource sharing, you should set following header on the requested server http://gateway.fpts..vn
.
To allow requests from any domain, use *
as a wildcard (less secure):
Access-Control-Allow-Origin: *
or
To allow requests from a particular domain:
Access-Control-Allow-Origin: http://www.requesting-server.
You can also check this post which addresses the same issue.
In addition to @Orions ment (https://stackoverflow./a/37678620/633781), you need to provide following header in your request to a server, to make it work:
Origin: <your domain, e.g. http://example.>
As far as I remember, jQuery does this automatically for you. Nevertheless, you can check the request headers in your browser's Dev tools to make sure it does. You can add your own headers to requests made with jQuery, though (https://api.jquery./jquery.ajax/)
You have to import jquery library from below link to use this code. https://jquery./download/
$.get( "http://gateway.fpts..vn/monitor/realtime/?s=aaa", function( data ) {
console.log(data);
});
You can make an ajax request an then get the data, something like this:
$.ajax({
url: "http://gateway.fpts..vn/monitor/realtime/?s=aaa",
}).done(function(data) {
$("body").html(data);
});
Make sure to include jquery if you use this.
Because your data is in JSON
form, you can use a shorthand for that using $.getJson()
. Download jQuery library and include on top of every script. Then place the following snippet in a separate script below the jQuery library.
(function($){
$(function(){
$.getJson( "http://gateway.fpts..vn/monitor/realtime/?s=aaa", function(data) {
console.log(data);
// do something with data....
});
});
})(jQuery || window.jQuery);
本文标签: How to get data request from link url in javascriptStack Overflow
版权声明:本文标题:How to get data request from link url in javascript? - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1744634059a2616715.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论