javascript - Problem finding the difference in days between two dates - Stack Overflow

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I have been using a tidy little routine that I found here to calculate the difference in days between two dates in AS3. I am getting some strange results and I am wondering if any of you inter-codal-mega-lords can shed some light?

Why is Q1 of 2010 ing up one day short, when in all other cases the routine is performing fine?

Many thanks in advance to anyone who can help!

        function countDays( startDate:Date, endDate:Date ):int
        {
            var oneDay:int = 24*60*60*1000; // hours*minutes*seconds*milliseconds
            var diffDays:int = Math.abs((startDate.getTime() - endDate.getTime())/(oneDay));
            return diffDays;
        }

        countDays( new Date( 2010, 00, 01 ), new Date( 2011, 00, 01 ) );
        // returns 365, which is correct

        countDays( new Date( 2010, 00, 01 ), new Date( 2010, 03, 01 ) );
        // returns 89, which is 1 day short

        countDays( new Date( 2010, 03, 01 ), new Date( 2010, 06, 01 ) );
        // returns 91, which is correct

        countDays( new Date( 2010, 06, 01 ), new Date( 2010, 09, 01 ) );
        // returns 92, which is correct

        countDays( new Date( 2010, 09, 01 ), new Date( 2011, 00, 01 ) );
        // returns 92, which is correct

I have been using a tidy little routine that I found here to calculate the difference in days between two dates in AS3. I am getting some strange results and I am wondering if any of you inter-codal-mega-lords can shed some light?

Why is Q1 of 2010 ing up one day short, when in all other cases the routine is performing fine?

Many thanks in advance to anyone who can help!

        function countDays( startDate:Date, endDate:Date ):int
        {
            var oneDay:int = 24*60*60*1000; // hours*minutes*seconds*milliseconds
            var diffDays:int = Math.abs((startDate.getTime() - endDate.getTime())/(oneDay));
            return diffDays;
        }

        countDays( new Date( 2010, 00, 01 ), new Date( 2011, 00, 01 ) );
        // returns 365, which is correct

        countDays( new Date( 2010, 00, 01 ), new Date( 2010, 03, 01 ) );
        // returns 89, which is 1 day short

        countDays( new Date( 2010, 03, 01 ), new Date( 2010, 06, 01 ) );
        // returns 91, which is correct

        countDays( new Date( 2010, 06, 01 ), new Date( 2010, 09, 01 ) );
        // returns 92, which is correct

        countDays( new Date( 2010, 09, 01 ), new Date( 2011, 00, 01 ) );
        // returns 92, which is correct

• javascript
• actionscript-3

Share Improve this question Follow edited May 23, 2017 at 12:11 CommunityBot 111 silver badge asked Jun 9, 2010 at 21:21 JamesJames 64188 silver badges1717 bronze badges

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3 Answers 3

Sorted by: Reset to default 4

Below should work:

    function countDays( startDate:Date, endDate:Date ):int 
    { 
        var oneDay:int = 24*60*60*1000; // hours*minutes*seconds*milliseconds 
        var diffDays:int = Math.round(Math.abs((startDate.getTime() - endDate.getTime())/(oneDay))); 
        return diffDays; 
    } 

Daylight Savings, maybe? You lose an hour in the first quarter, so your function must be truncating the int instead of rounding.

Can't be sure. I'd guess at a rounding/truncation error.

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