admin管理员组文章数量:1391943
Is it possible to re-run the function 'check' without calling check() in the else statement? Maybe call itself somehow?
If I have multiple instances of this function, they end up calling each other, unless I change it to check1, check2, etc.. While this is prob. a performance killer, I was just trying it out for a prototype app.
(function check () {
if (typeof foo !='undefined') {
// do stuff
} else {
console.log("Failed to load, trying again");
setTimeout(function(){ check(); }, 10);
}
})();
Is it possible to re-run the function 'check' without calling check() in the else statement? Maybe call itself somehow?
If I have multiple instances of this function, they end up calling each other, unless I change it to check1, check2, etc.. While this is prob. a performance killer, I was just trying it out for a prototype app.
(function check () {
if (typeof foo !='undefined') {
// do stuff
} else {
console.log("Failed to load, trying again");
setTimeout(function(){ check(); }, 10);
}
})();
Share
Improve this question
asked Nov 16, 2012 at 8:09
SkinnyG33kSkinnyG33k
1,7414 gold badges24 silver badges30 bronze badges
2
-
they end up calling each other
Example please – Alvin Wong Commented Nov 16, 2012 at 8:13 - Why would you have two functions named check? Maybe setInterval is what you want? You can do a clearInterval inside to stop iteration... – beatgammit Commented Nov 16, 2012 at 8:14
3 Answers
Reset to default 6Well, you could use arguments.callee
to call it, but it's a bad idea, a performance hit, and it isn't valid in strict mode.
What you've quoted is valid JavaScript and should not make check
call another check
function if you have one alongside it. Sadly, though, it will in IE8 and earlier because they quite incorrectly leak the name check
to the surrounding scope (named function expressions do not add the function name to the surrounding scope like function declarations do — except on IE8 and earlier [and that's not all they get wrong with them]).
So the solution is to use an anonymous function to hide a named one:
(function() {
// A check function
check();
function check () {
if (typeof foo !='undefined') {
// do stuff
} else {
console.log("Failed to load, trying again");
setTimeout(function(){ check(); }, 10);
}
}
})();
(function() {
// A plete different one
check();
function check () {
if (typeof foo !='undefined') {
// do other stuff
} else {
console.log("Failed to load, trying again");
setTimeout(function(){ check(); }, 10);
}
}
})();
How about using an interval instead removing the need to call itself, as this will be done automatically until you clear the interval:
(function(){
var interval = setInterval(function(){
if(typeof foo != 'undefined'){
clearInterval(interval);
// do stuff
}else{
console.log("Failed to load, trying again");
}
},10)
})();
Why not do something like this instead:
var inter;
function check() {
if (typeof foo !== 'undefined') {
clearInterval(inter);
// do stuff
} else {
console.log("Failed to load, trying again");
}
}
inter = setInterval(check, 10);
It's not a drop in replacement, but I think it's better style.
本文标签: How can I call an anonymous function from inside itself in JavaScriptStack Overflow
版权声明:本文标题:How can I call an anonymous function from inside itself in JavaScript? - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1744579955a2613859.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论