conditional operator - Javascript shorthand for true or false in function - Stack Overflow

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Is there a shorthand way of doing this so that the oute is always true or false?

function trueFalse() {
  if( a == 1 ) {
    return true;
  } else {
    return false;
  }
}

Something like return true:false; and no need for the else section?

Thanks.

Is there a shorthand way of doing this so that the oute is always true or false?

function trueFalse() {
  if( a == 1 ) {
    return true;
  } else {
    return false;
  }
}

Something like return true:false; and no need for the else section?

Thanks.

• javascript
• conditional-operator

Share Improve this question Follow edited Dec 30, 2022 at 16:49 Tristan F.-R. 4,22433 gold badges2626 silver badges5555 bronze badges asked Jun 14, 2013 at 15:10 martinmartin 41311 gold badge77 silver badges2222 bronze badges 1

• 3 a == 1 is already a boolean. – SLaks Commented Jun 14, 2013 at 15:13

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 5

That would be:

function trueFalse(){
  return a === 1;
}

Also, as much as possible, use strict parison.

(a few years after OP question but this would now also work)

ES6 shorthand would allow you to use a conditional operator:

const trueFalse = a === 1 ? true : false

Or even shorter but a bit less readable:

const trueFalse = a === 1

https://developer.mozilla/en-US/docs/Web/JavaScript/Reference/Operators/Conditional_Operator

Just to make it even shorter and allow for any parison...

const trueFalse = (a, b) => a === b;

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