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I have the following date format in a MySQL database and was wondering what would be the best method to reformat this date and output what I have in mind.
MySQL: 2012-04-12
Desired Output: Thursday, April 12 2012
Perhaps I could format it in the MySQL query? Or with Java script?
Could anyone provide a sample of both so I could learn?
I have the following date format in a MySQL database and was wondering what would be the best method to reformat this date and output what I have in mind.
MySQL: 2012-04-12
Desired Output: Thursday, April 12 2012
Perhaps I could format it in the MySQL query? Or with Java script?
Could anyone provide a sample of both so I could learn?
Share Improve this question edited May 18, 2014 at 9:13 elboletaire 5,3872 gold badges37 silver badges47 bronze badges asked Apr 12, 2012 at 14:24 suchislifesuchislife 17 Answers
Reset to default 3Try moment.js
e.g. var day = moment("2012-04-12", "DDDD, MMMM DD YYYY");
You have a lot of ways to do this:
- With MySQL, using
DATE_FORMAT
http://dev.mysql./doc/refman/5.5/en/date-and-time-functions.html#function_date-format - With PHP, using
strtotime
anddate
:date('J, M d Y', strtotime($yourdate))
- With JavaScript, splitting the date at "-" and then creating your date again with
new Date()
- Also (like explained by t0s6i), with JavaScript, you can use the library momentjs to do something like this:
date = moment("2012-04-12", "DDDD, MMMM DD YYYY");
.
For formatting in javascript using jquery, loo at this other post.
Best JavaScript Date Parser & Formatter?
I would probably format with the code actually pulling the date form MySql. What language are you using? php, asp, java...?
PHP has a convenient class for reading dates in a specific format:
http://www.php/manual/en/datetime.createfromformat.php
$result = mysql_query("select date_column from table_name limit 1");
$array = mysql_fetch_array($result);
print DateTime::createFromFormat('Y-m-d')->format('jS M Y');
The best approach is usually to format the value with the PHP side just before outputting it:
$date = DateTime::createFromFormat('Y-m-d', $row['the_date']);
echo $date->format('J, M d Y');
When you have an date with mysql, it's you receive it in Php no?
for optimize your performance, use the native php date function to convert your mysql date , it's easy:
read just the official PHP doc => http://php/manual/fr/function.date.php
Php treatments as more fast than javascript treatments.
From javascript you can format your date using below function, DEMO
Note: The below function additionally displays sup for date (ex: 3rd, 12th e.t.c). Remove all the if..else if
in below code if you don't want it.
function formatDate(d) {
var d_names = new Array("Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday");
var m_names = new Array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
var curr_day = d.getDay();
var curr_date = d.getDate();
var sup = "";
if (curr_date == 1 || curr_date == 21 || curr_date == 31) {
sup = "st";
} else if (curr_date == 2 || curr_date == 22) {
sup = "nd";
} else if (curr_date == 3 || curr_date == 23) {
sup = "rd";
} else {
sup = "th";
}
var curr_month = d.getMonth();
var curr_year = d.getFullYear();
return d_names[curr_day] + " " + m_names[curr_month] + " " + curr_date + sup + " " + curr_year;
}
Reference: Javascript Date formatting (above is modified version of Format #5)
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