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I am new in JQuery. I was playing with some JQuery, I visited this jsfiddle . I want to make exactly form like this. I copy all the code into my test.html. Here is my code.
<html>
<head>
<title>
TEST
</title>
<script>
$(".container").on("change", ".a2 input[name^='selection_']", function
(event) {
if ($(this).val() == "name") {
$(this).parent().find('.url').css({
'visibility': 'hidden',
'display': 'none'
});
$(this).parent().find('.text').css({
'visibility': 'visible',
'display': 'block'
});
} else {
$(this).parent().find('.text').css({
'visibility': 'hidden',
'display': 'none'
});
$(this).parent().find('.url').css({
'visibility': 'visible',
'display': 'block'
});
}
});
$('.clone').click(function () {
var p = $('.a2').length;
var cloned = $('.a2:first').clone()
.find('input:radio').attr('name', 'selection_' + ++p).end()
.appendTo('.container');
});
</script>
<style>
.a2 .url {
visibility:hidden;
display:none;
}
</style>
</head>
<body>
<div class="container">
<div class="a2">
<input type="radio" name="selection_1" value="name" checked="checked"
/>Name
<input type="radio" name="selection_1" value="url" />URL
<div class="text">
<textarea name="name[]">Enter name:</textarea>
</div>
<div class="url">
<textarea name="url[]">http://</textarea>
</div>
</div>
</div>
<input type="button" class="clone" value="Clone" />
</body>
</html>
The result of this code is, the button clone not working, same with the radio button. My question is, how to copy the jquery code in jsfiddle into html form. Thanks in advance
I am new in JQuery. I was playing with some JQuery, I visited this jsfiddle . I want to make exactly form like this. I copy all the code into my test.html. Here is my code.
<html>
<head>
<title>
TEST
</title>
<script>
$(".container").on("change", ".a2 input[name^='selection_']", function
(event) {
if ($(this).val() == "name") {
$(this).parent().find('.url').css({
'visibility': 'hidden',
'display': 'none'
});
$(this).parent().find('.text').css({
'visibility': 'visible',
'display': 'block'
});
} else {
$(this).parent().find('.text').css({
'visibility': 'hidden',
'display': 'none'
});
$(this).parent().find('.url').css({
'visibility': 'visible',
'display': 'block'
});
}
});
$('.clone').click(function () {
var p = $('.a2').length;
var cloned = $('.a2:first').clone()
.find('input:radio').attr('name', 'selection_' + ++p).end()
.appendTo('.container');
});
</script>
<style>
.a2 .url {
visibility:hidden;
display:none;
}
</style>
</head>
<body>
<div class="container">
<div class="a2">
<input type="radio" name="selection_1" value="name" checked="checked"
/>Name
<input type="radio" name="selection_1" value="url" />URL
<div class="text">
<textarea name="name[]">Enter name:</textarea>
</div>
<div class="url">
<textarea name="url[]">http://</textarea>
</div>
</div>
</div>
<input type="button" class="clone" value="Clone" />
</body>
</html>
The result of this code is, the button clone not working, same with the radio button. My question is, how to copy the jquery code in jsfiddle into html form. Thanks in advance
Share Improve this question asked Jun 16, 2017 at 3:19 Azim AzmanAzim Azman 971 gold badge1 silver badge9 bronze badges 6- 2 include the jquery script in your html make sure you load the jquery script before all you code – guradio Commented Jun 16, 2017 at 3:20
- You have not included the main jQuery script in your code. Add that in your html head and your code should work – Colwin Commented Jun 16, 2017 at 3:21
- how to include it ? i have include this <script src="code.jquery./jquery-1.7.2.min.js"></script> but still not working – Azim Azman Commented Jun 16, 2017 at 3:22
- put your code just before the </body> or put your js inside document .ready – guradio Commented Jun 16, 2017 at 3:25
-
a) include jquery, b) wrap your code in
$(function() { ... your code ... });
so your code waits for DOM to be ready before accessing DOM – Jaromanda X Commented Jun 16, 2017 at 3:33
3 Answers
Reset to default 3Download JQuery or use its CDN (the same as the one in the snippet), then put it inside the head
above all other js
files (if you have more) so that JQuery
will be loaded first before all the other scripts
It would be preferable if you include the script after the body
tag so that all elements have been loaded before the scripts fire.
Note: I didn't separate the css
and scripts
in the snippet so that OP can see where to place the needed ponents
<html>
<head>
<title>
TEST
</title>
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<style>
.a2 .url {
visibility: hidden;
display: none;
}
</style>
</head>
<body>
<div class="container">
<div class="a2">
<input type="radio" name="selection_1" value="name" checked="checked" />Name
<input type="radio" name="selection_1" value="url" />URL
<div class="text">
<textarea name="name[]">Enter name:</textarea>
</div>
<div class="url">
<textarea name="url[]">http://</textarea>
</div>
</div>
</div>
<input type="button" class="clone" value="Clone" />
</body>
<script>
$(".container").on("change", ".a2 input[name^='selection_']", function(event) {
if ($(this).val() == "name") {
$(this).parent().find('.url').css({
'visibility': 'hidden',
'display': 'none'
});
$(this).parent().find('.text').css({
'visibility': 'visible',
'display': 'block'
});
} else {
$(this).parent().find('.text').css({
'visibility': 'hidden',
'display': 'none'
});
$(this).parent().find('.url').css({
'visibility': 'visible',
'display': 'block'
});
}
});
$('.clone').click(function() {
var p = $('.a2').length;
var cloned = $('.a2:first').clone()
.find('input:radio').attr('name', 'selection_' + ++p).end()
.appendTo('.container');
});
</script>
</html>
Include jquery script on your head section
<script type="text/javascript" src="//ajax.googleapis./ajax/libs/jquery/1.7.2/jquery.min.js"></script>
You can download jquery.js
file from www.jquery./download/ then put in the one place :
<script type="text/javascript" src="path of your jquery.js file + your jquery file name " ><script>
Note : You should write this code before your scripts !
本文标签: javascriptHow to add Jquery script into htmlStack Overflow
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