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My main task is to update the markers on the map.

Notation:

Markers that are displayed in real-time on the map:

var markers = [
  { 'lat':10, 'lng':10, 'type':'simple'},
  { 'lat':20, 'lng':20, 'type':'simple'},
  { 'lat':40, 'lng':40, 'type':'cluster'}
]

New markers which should be on the map:

var newMarkers = [
  { 'lat':10, 'lng':10, 'type':'simple'},
  { 'lat':20, 'lng':20, 'type':'simple'},
  { 'lat':30, 'lng':30, 'type':'simple'},
  { 'lat':50, 'lng':50, 'type':'simple'}
]

Thus the problem is reduced to the subtask which I want to find solution: update the array of objects - markers from the another array of objects - newMarkers.

Thus, need to perform the following manipulation with markers array:

1. Remove objects from markers which are not in newMarkers (pared by three properties: lat, lng, type).
2. Add objects from newMarkers into markers if not exist (pared by lat, lng). If marker exist (by two properies: lat, lng) is necessary to update it, i.e. to replace by a new marker from newMarkers.

My solution ineffective since it is because it is performed for a long time on large number of markers.

Updated markers array should look like:

console.log(markers)
{ 'lat':10, 'lng':10, 'type':'simple'},
{ 'lat':20, 'lng':20, 'type':'simple'},
{ 'lat':30, 'lng':30, 'type':'simple'},
{ 'lat':50, 'lng':50, 'type':'simple'}

My main task is to update the markers on the map.

Notation:

Markers that are displayed in real-time on the map:

var markers = [
  { 'lat':10, 'lng':10, 'type':'simple'},
  { 'lat':20, 'lng':20, 'type':'simple'},
  { 'lat':40, 'lng':40, 'type':'cluster'}
]

New markers which should be on the map:

var newMarkers = [
  { 'lat':10, 'lng':10, 'type':'simple'},
  { 'lat':20, 'lng':20, 'type':'simple'},
  { 'lat':30, 'lng':30, 'type':'simple'},
  { 'lat':50, 'lng':50, 'type':'simple'}
]

Thus the problem is reduced to the subtask which I want to find solution: update the array of objects - markers from the another array of objects - newMarkers.

Thus, need to perform the following manipulation with markers array:

1. Remove objects from markers which are not in newMarkers (pared by three properties: lat, lng, type).
2. Add objects from newMarkers into markers if not exist (pared by lat, lng). If marker exist (by two properies: lat, lng) is necessary to update it, i.e. to replace by a new marker from newMarkers.

My solution ineffective since it is because it is performed for a long time on large number of markers.

Updated markers array should look like:

console.log(markers)
{ 'lat':10, 'lng':10, 'type':'simple'},
{ 'lat':20, 'lng':20, 'type':'simple'},
{ 'lat':30, 'lng':30, 'type':'simple'},
{ 'lat':50, 'lng':50, 'type':'simple'}

• javascript
• arrays
• algorithm
• leaflet
• lodash

Share Improve this question Follow asked Feb 10, 2017 at 1:16 AndreiAndrei 1,37344 gold badges2121 silver badges3535 bronze badges 11

• what is your current solution? – hackerrdave Commented Feb 10, 2017 at 1:17
• do we know anything about the data? is it in any sorted order? are markers unique per pairing of lat/lng? – hackerrdave Commented Feb 10, 2017 at 1:18
• 2 Your resulting array is exactly the same as newMarkers, and I don't see how it could ever be different - you're effectively getting rid of anything not in the newMarkers array – Booboobeaker Commented Feb 10, 2017 at 1:19
• markers = newMarkers, judging on your example dataset. – Lee Commented Feb 10, 2017 at 1:22
• @hackerrdave my solution, but it works slow on large markers count -pastebin./NnBU9Fpz – Andrei Commented Feb 10, 2017 at 1:26

 |  Show 6 more ments

2 Answers 2

Sorted by: Reset to default 6

Just to re-state what was clarified in the ments after the question...

The 1st element in each of markers and newMarkers are equal by value but not by reference, and that matters. Thus you want all the items from newMarkers in your updated list, but if an element in newMarkers has all the same property values as an already existing element in markers then you want to keep the original element from markers.

The solution below loops through all the values in newMarkers and, if an element in markers has the same property values, the markers reference is used, otherwise the newMarkers reference is used.

const markers = [
  { 'lat':10, 'lng':10, 'type':'simple'},
  { 'lat':20, 'lng':20, 'type':'simple'},
  { 'lat':40, 'lng':40, 'type':'cluster'}
];

const newMarkers = [
  { 'lat':10, 'lng':10, 'type':'simple'},
  { 'lat':20, 'lng':20, 'type':'simple'},
  { 'lat':30, 'lng':30, 'type':'simple'},
  { 'lat':50, 'lng':50, 'type':'simple'}
];

const updatedMarkers = newMarkers.map(newMarker =>
  markers.reduce((accumulator, origMarker) => (
    (
      origMarker.lat  === newMarker.lat  &&
      origMarker.lng  === newMarker.lng  &&
      origMarker.type === newMarker.type
    ) ? origMarker : accumulator
  ), newMarker)
);

markers.map((marker, idx) => {
  console.log(`Element #${idx} from markers is present: ${!!(updatedMarkers.indexOf(marker) + 1)}`);
});
newMarkers.map((marker, idx) => {
  console.log(`Element #${idx} from newMarkers is present: ${!!(updatedMarkers.indexOf(marker) + 1)}`);
});

If I'm understanding your problem correctly, you want to reflect changes in newMarkers in markers without simply replacing the reference on markers.

// remove (everything in markers that's not in newMarkers) from markers
_.pull(markers, ..._.difference(markers, newMarkers)); 
// push (everything in newMarkers that's not in markers) to markers
markers.push(..._.difference(newMarkers, markers));

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