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I have 2 kinds of data.

One data is something like this

ws=eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9

and the another data like this

ws=eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9;utmz=111872281.1437151704.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none);

I wanna get the ws value, like

eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9

But i got problems for split the ";" character. Because sometime the data have the character, but sometimes it doesn't have that character.

I already tried using

ws=([^]*);?

and

ws=([^]*)[;?]

and I still doesn't get the correct data. Thank you very much.

I have 2 kinds of data.

One data is something like this

ws=eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9

and the another data like this

ws=eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9;utmz=111872281.1437151704.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none);

I wanna get the ws value, like

eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9

But i got problems for split the ";" character. Because sometime the data have the character, but sometimes it doesn't have that character.

I already tried using

ws=([^]*);?

and

ws=([^]*)[;?]

and I still doesn't get the correct data. Thank you very much.

• javascript
• regex

Share Improve this question Follow asked Jul 25, 2015 at 11:11 user2565496user2565496 2511 gold badge11 silver badge66 bronze badges

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2 Answers 2

Sorted by: Reset to default 2

You can use:

/\bws=([^;]*)/

and grab captured group #1

RegEx Demo

([^;]*) will match 0 or more of any character that is not ;

I would use this:

ws=(.*?)(;|$)

Try it online: http://regexr./3bfbv

• ws= searches for that exact text
• ( starts the matching group
• .*? searches for any characters, but as few characters as possbile ("non-greedy")
• ) stops the matching group
• (;|$) searches for either a ; or the end of the text (or the line)

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