javascript - Regex to validate comma-separated numbers with optional fractional parts - Stack Overflow

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Using JavaScript, I need to accept only numbers and mas.

The regex pattern I am using is as follows

 var pattern = /^[-+]?[0-9]+(\.[0-9]+)?$/;

How do I accept mas in the above pattern So that values like 3200 or 3,200 or 3,200.00 and so are valid?

There are similar questions that only partially deal with this:

• Regex validation for numbers with ma separator (only whole numbers with no fractional part)
• Decimal number regular expression, where digit after decimal is optional (no ma separation, fractional part limited to 1 digit)
• Javascript function need allow numbers, dot and ma (the dots, mas and digits are matched in any order)

Using JavaScript, I need to accept only numbers and mas.

The regex pattern I am using is as follows

 var pattern = /^[-+]?[0-9]+(\.[0-9]+)?$/;

How do I accept mas in the above pattern So that values like 3200 or 3,200 or 3,200.00 and so are valid?

There are similar questions that only partially deal with this:

• Regex validation for numbers with ma separator (only whole numbers with no fractional part)
• Decimal number regular expression, where digit after decimal is optional (no ma separation, fractional part limited to 1 digit)
• Javascript function need allow numbers, dot and ma (the dots, mas and digits are matched in any order)

• javascript
• regex

Share Improve this question Follow edited Aug 25, 2019 at 21:28 Wiktor Stribiżew 628k4141 gold badges498498 silver badges614614 bronze badges asked Oct 27, 2015 at 12:54 user1339913user1339913 1,02744 gold badges1616 silver badges3737 bronze badges 1

• 1 Why not test if the string is a valid number instead of trying to match it with a regex? – James Montagne Commented Oct 27, 2015 at 13:01

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1 Answer 1

Sorted by: Reset to default 4

Use the following regex:

^[-+]?(?:[0-9]+,)*[0-9]+(?:\.[0-9]+)?$

See regex demo

The basic change here is the addition of (?:[0-9]+,)* subpattern that matches:

• [0-9]+ - 1 or more digits
• , - a ma

0 or more times (thanks to * quantifier).

I also used non-capturing groups so that regex output is "cleaner".

If you need to check for 3-digit groups in the number, use

^[-+]?[0-9]+(?:,[0-9]{3})*(?:\.[0-9]+)?$

See another demo

Here, (?:,[0-9]{3})* matches 0 or more sequences of a ma and 3-digit substrings ([0-9]{3}). {3} is a limiting quantifier matching exactly 3 occurrences of the preceding subpattern.

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