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Apologies for the image and not uploading a proper table -- still haven't figured out how to do that.
I have a sample data set of agents with multiple columns with random values.
I am trying to use either index-match or Filter functions to allow me to search for the owner of a specific value.
Because the value being search could be in any column, I can't call index-match and the Filter function has the same issue.
Any help would be appreciated.
Apologies for the image and not uploading a proper table -- still haven't figured out how to do that.
I have a sample data set of agents with multiple columns with random values.
I am trying to use either index-match or Filter functions to allow me to search for the owner of a specific value.
Because the value being search could be in any column, I can't call index-match and the Filter function has the same issue.
Any help would be appreciated.
Share Improve this question asked Mar 23 at 22:25 haby22haby22 8510 bronze badges 2 |1 Answer
Reset to default 0I don't know if that is possible with a single formula, but I managed to do what you want with multiple small formulas. Let's say this is your Excel table:
A | B | C | D | E | F | |
---|---|---|---|---|---|---|
1 | Name | Column1 | Column2 | Column3 | Column4 | Column5 |
2 | Agent1 | 883 | 1849 | 868 | 778 | 883 |
3 | Agent2 | 1758 | 1872 | 722 | 859 | 1556 |
4 | Agent3 | 1208 | 1418 | 1707 | 577 | 875 |
5 | Agent4 | 1277 | 959 | 669 | 503 | 1895 |
6 | Agent5 | 1541 | 635 | 526 | 1585 | 592 |
7 | Agent6 | 1857 | 1673 | 1778 | 1244 | 777 |
8 | Agent7 | 1177 | 1843 | 987 | 1213 | 808 |
9 | Agent8 | 1257 | 1474 | 526 | 1537 | 1624 |
10 | Agent9 | 1487 | 1348 | 1786 | 1172 | 723 |
11 | Agent10 | 715 | 1404 | 1437 | 1178 | 1783 |
12 | Agent11 | 1697 | 1831 | 908 | 1019 | 1487 |
13 | Agent12 | 1273 | 573 | 1313 | 1398 | 1625 |
Here is what we will do:
- Find the match in each column:
First we use the formula =IFNA(MATCH($H$3;$B$2:$B$13;0);0) This will search for the index in the range that matches the value, if no value is present, then the index will be 0. For column B this will be the results
1541 -> 5
715 -> 10
999 -> 0
We will use this match function for each column
- Create the references for the Column "A":
We will use the results of the previous formula to create the reference for column A with the formula =IF(J5<>0;"A" & J5 + 1;"") This will check if the index is different than cero and then format the cell as a concatenation of A + the index plus one:
1541 -> 5 -> A6
715 -> 10 -> A11
999 -> 0 -> ""
- Find the first not empty reference:
The previous step will give us a range of references if multiple value matches, for this, we will use this formula to get the first non blank value:
=INDEX($K$5:$K$9;MATCH(FALSE;EXACT("";$K$5:$K$9);0))
The formula will lookup the range of references and return the first non empty value:
Range | Result |
---|---|
"" | A2 |
"" | |
A2 | |
"" | |
"" |
- Fetch the value with the reference
Once we have all the previous values we can fetch the actual value from column A with the recerence using the formula =INDIRECT($K$5;TRUE)
The function "INDIRECT" will receive the value "A2" and use if as a reference for the cell A2 giving us the value "Agent2" in the original table.
Result Table
Here we have all the formulas used to find the match:
H | I | J | K | L | |
---|---|---|---|---|---|
1 | |||||
2 | Value | Agent | |||
3 | 635 | =INDIRECT($K$5;TRUE) | |||
4 | |||||
5 | Column1 | =IFNA(MATCH($H$3;$B$2:$B$13;0);0) | =IF(J5<>0;"A" & J5 + 1;"") | =INDEX($K$5:$K$9;MATCH(FALSE;EXACT("";$K$5:$K$9);0)) | |
6 | Column2 | =IFNA(MATCH($H$3;$C$2:$C$13;0);0) | =IF(J6<>0;"A" & J6 + 1;"") | ||
7 | Column3 | =IFNA(MATCH($H$3;$D$2:$D$13;0);0) | =IF(J7<>0;"A" & J7 + 1;"") | ||
8 | Column4 | =IFNA(MATCH($H$3;$E$2:$E$13;0);0) | =IF(J8<>0;"A" & J8 + 1;"") | ||
9 | Column5 | =IFNA(MATCH($H$3;$F$2:$F$13;0);0) | =IF(J9<>0;"A" & J9 + 1;"") | ||
10 |
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=TOCOL(Ifs(B2:F13=K4,A2:A13),2)
– P.b Commented Mar 23 at 22:38