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The table structure is as below
TABLE A
ID | STATUS | STATUS CODE |
---|---|---|
10 | ABS | 1,2 |
11 | ABS | 3,4 |
The table structure is as below
TABLE A
ID | STATUS | STATUS CODE |
---|---|---|
10 | ABS | 1,2 |
11 | ABS | 3,4 |
How to split as
ID | STATUS Code |
---|---|
10 | 1 |
10 | 2 |
11 | 3 |
11 | 4 |
This is what I tried but the ID is not repeating
WITH T_LIST AS (
select id, status, split(status_code, ',') as code_array
from TABLE A
where status is not null
and status = 'ABS'
)
SELECT TL.id, TL.code_array
FROM T_LIST TL
CROSS JOIN UNNEST(TL.code_array) as INFO
ID | STATUS Code |
---|---|
10 | 1 |
2 | |
11 | 3 |
4 |
1 Answer
Reset to default 0I replicate your query with the use of SPLIT
and CROSS JOIN UNNEST
and it gives me your expected result. Split in status code to have your values in array and have CROSS JOIN UNNEST
properly to have them group together.
Table:
ID | Status | Code |
---|---|---|
10 | ABS | 1,2 |
11 | ABS | 3,4 |
Here is the code I use:
WITH T\_LIST AS (
SELECT id, status, SPLIT(CODE, ',') AS code\_array
FROM data-sandbox-\*\*\*\*\*\*.SIB3.SIB4
WHERE status IS NOT NULL
AND status = 'ABS'
)
SELECT
TL.id
, INFO AS CODE
FROM T\_LIST TL
CROSS JOIN UNNEST(TL.code\_array) AS INFO
ORDER BY
TL.id
, INFO;
Here is the screenshot of my replication:
本文标签: SPLIT in BigQueryStack Overflow
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