JavaScript: Regex - Cannot startend with punctuation, no repeating punctuation - Stack Overflow

admin管理员组

文章数量:1394593

I'm trying to create a Regex. The rules are:

1) Only letters (both upper and lower), numbers, periods (.) and underscores (_)

2) Must begin and end with letter or number (i.e. no periods/underscores)

3) Cannot have multiple punctuations in a row, of any kind (no .. or ._ or _. or __ or .._. etc)

4) Must contain at least 2 letters (either upper or lower or both, doesn't matter)

5) No less than 3 chars, no more than 25 chars

So far, what I have is:

^((?!.*[\._]{2})[A-Za-z0-9\._]{3,25})$

Which is close-ish. I've got rules 1, 3 and 5, but cannot figure out 2 and 4.

I thought that

(([A-Za-z0-9]?)([A-Za-z0-9\._]+)([A-Za-z0-9]?)){3,25}

would get rule 2, but it just breaks it.

I've been working on this for a couple hours, but none of the solutions I can find, or can e up with, are quite what I'm looking for.

An explanation of the Regex statement you provide would be greatly appreciated, but is not entirely necessary.

EDIT 1

As per noob's suggestion:

^((?!.*[\._]{2})(([\w\d\.]+)){3,25})$

EDIT 2

Valid:

1rockit.man
q3w
e4.45r.d.2
sp_am

(and anything else between 3 and 25 characters, without leading or repeating punctuation)

Invalid:

.ret.
123
12a
ret..wer
super_.duper
_petrat
petrat_

I'm trying to create a Regex. The rules are:

1) Only letters (both upper and lower), numbers, periods (.) and underscores (_)

2) Must begin and end with letter or number (i.e. no periods/underscores)

3) Cannot have multiple punctuations in a row, of any kind (no .. or ._ or _. or __ or .._. etc)

4) Must contain at least 2 letters (either upper or lower or both, doesn't matter)

5) No less than 3 chars, no more than 25 chars

So far, what I have is:

^((?!.*[\._]{2})[A-Za-z0-9\._]{3,25})$

Which is close-ish. I've got rules 1, 3 and 5, but cannot figure out 2 and 4.

I thought that

(([A-Za-z0-9]?)([A-Za-z0-9\._]+)([A-Za-z0-9]?)){3,25}

would get rule 2, but it just breaks it.

I've been working on this for a couple hours, but none of the solutions I can find, or can e up with, are quite what I'm looking for.

An explanation of the Regex statement you provide would be greatly appreciated, but is not entirely necessary.

EDIT 1

As per noob's suggestion:

^((?!.*[\._]{2})(([\w\d\.]+)){3,25})$

EDIT 2

Valid:

1rockit.man
q3w
e4.45r.d.2
sp_am

(and anything else between 3 and 25 characters, without leading or repeating punctuation)

Invalid:

.ret.
123
12a
ret..wer
super_.duper
_petrat
petrat_

• javascript
• regex

Share Improve this question Follow edited Feb 27, 2016 at 8:26 Aprillion 22.4k66 gold badges5858 silver badges9191 bronze badges asked Feb 27, 2016 at 6:13 BirrelBirrel 4,83477 gold badges4141 silver badges7979 bronze badges 5

• 1 Use shorthand operators like \w and \d. Easier to prehend. \w also include _ so that's covered. – user2705585 Commented Feb 27, 2016 at 6:17
• You might want to include a few valid and invalid matches for quick testing. – user2705585 Commented Feb 27, 2016 at 6:27
• 1rockit.man and e4.45r.d.2 are invalid according to condition 2. Cannot begin or end with non-letter/number. You might wanna check again the given condition or the example. – user2705585 Commented Feb 27, 2016 at 6:37
• @noob cannot begin with non-letter or non-number. i.e., must begin and end with either letter or number. I'll make it more clear in the post – Birrel Commented Feb 27, 2016 at 6:40
• Okay. non-letter/number seems to be confusing. – user2705585 Commented Feb 27, 2016 at 6:40

Add a ment  | 

4 Answers 4

Sorted by: Reset to default 7

Based upon your conditions I came up with following regex. It's only modification over your current regex.

Regex: ^(?=.*[A-Za-z].*[A-Za-z])([A-Za-z0-9]((?!.*[\._]{2})([\w\d\.]{1,23}))[A-Za-z0-9])$

Explanation:

• The first part (?=.*[A-Za-z].*[A-Za-z]) checks for whole string to have two characters separated by anything (that's pretty much the case here).

• I added checks on the beginning and end of string which should be either letter or number.

• Apart from that the length will also vary now as first and last character is counted rest of the length will be only 23 characters.

Regex101 Demo

Building the regex from the rules (in an order of convenience):

• both upper and lower case => use case insensitive flag //i
• letters, numbers, underscore and period => [\w.]*
• 3-25 characters => ^[\w.]{3,25}$
• cannot begin or end with period or underscore => (?!^[\W_]|[W_]$)
  (notice uppercase \W meaning not \w)
• cannot contain 2 punctuation in a row => (?![\W_]{2})
• checking the negative lookahead in every position => (?:(?!...)[\w.]){3,25}
  (using non-capturing group (?:) instead of () because we don't need to save the group)
• at least 2 letters => (?:.*[a-z]){2} assuming i flag
• wrap into lookahead (not consuming any characters) so we can check multiple conditions => (?=(?:...))

The final regex literal:

/^(?=(?:.*[a-z]){2})(?:(?!^[\W_]|[\W_]{2}|[\W_]$)[\w.]){3,25}$/i

https://regex101./r/yK1cB3/5#javascript

---

FTR: in languages that support the x flag (ignoring whitespace inside the regex), you could make it more readable (see a workaround for javascript):

^
(?=
  (?:.*[a-z]){2}
)
(?:
   (?!^[\W_]|[\W_]{2}|[\W_]$)
   [\w.]
){3,25}
$

You can try with:

^(?=.*[a-zA-Z].*[a-zA-Z].*)[a-zA-Z0-9](?!.*[._]{2,}|.*[._]$)[._a-zA-Z0-9]{2,24}$

or, if you prefer make it using character classes like \w \d \s, you could use:

^(?=.*[a-zA-Z].*[a-zA-Z].*)\w(?!.*[._]{2,}|.*[._]$)(\w|[._]){2,24}$

http://regexr./3ct34

Takin part in ur riddle challenge. Here's my version. Would have nice performance as well :)

/^(?=(?:.*?[a-z]){2})[a-z\d](?!.*?[._]{2})[\w.]{1,23}[a-z\d]$/i

i flag for caseless matching where [a-z] is equivalent with alpha [a-zA-Z].
\w is a short for word character [A-Za-z0-9_] thus [\w.] will match allowed characters.
(?: opens a non capturing group mostly used for repitition or alternation (if group not needed).
(?= (?! lookarounds are zero-length assertions triggered at a certain position.

• Rule 2: Require one alnum [a-z\d] at ^ start and one at $ end
• Rule 1 & 5: No less than 3, no more than 25 with start/end substracted [\w.]{1,23}
• Rule 3: (?!.*?[._]{2}) no consecutive punctuation checked by negative lookahead.
• Rule 4: (?=(?:.*?[a-z]){2}) at least 2 letters checked with positive lookahead.

Check out demo at regex101

本文标签： JavaScript RegexCannot startend with punctuationno repeating punctuationStack Overflow