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Does anybody know why I get a Bad escapement error on JSHint using the follow code?

var regexS = '[\?&]' + name + '=([^&#]*)';

Does anybody know why I get a Bad escapement error on JSHint using the follow code?

var regexS = '[\?&]' + name + '=([^&#]*)';

• javascript
• jshint

Share Improve this question Follow edited Aug 9, 2014 at 17:41 fernandopasik 10.5k77 gold badges5151 silver badges5656 bronze badges asked Nov 1, 2012 at 0:25 user1790061user1790061 4911 silver badge33 bronze badges

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2 Answers 2

Sorted by: Reset to default 6

Just double escape the \

var regexS = '[\\?&]' + name + '=([^&#]*)';

Even though I'm guessing you'll be using this string for a Regex object, characters in a string must be escaped correctly. By default, a \ attempts to escape the next character. If you add an extra one to be like \\, it escapes the original \ and evaluates to a single \ in the final string.

\? isn't a valid escape character. Try replacing it with \\.

So it looks like:

var regexS = '[\\?&]' + name + '=([^&#]*)';

Keep in mind that "\" escapes the character that es after it. This is why \\ es out as a single slash (if you look at the source of this question you will find I needed to quadruple the \).

Other mon escape sequences are \n for newline and \t for tab.

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