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Simple question I hope you good people can help me with.

I'm using Firebase and I can display my firebase data on the page using:

var dbRef = firebase.database().ref().child('jumbotron/header');
dbRef.on('value', snap => container.innerText = snap.val());

But when I try to: console.log(dbRef) It displays as an object. I think this is because the reference is a URL. How can I console.log or print my firebase data as a string and eventually place it on my page using vanilla javascript. I can't find the solution in the FB documentation and there aren't any tutorials on the Google FB.

Any help is much appreciated. Thanks, All

Simple question I hope you good people can help me with.

I'm using Firebase and I can display my firebase data on the page using:

var dbRef = firebase.database().ref().child('jumbotron/header');
dbRef.on('value', snap => container.innerText = snap.val());

But when I try to: console.log(dbRef) It displays as an object. I think this is because the reference is a URL. How can I console.log or print my firebase data as a string and eventually place it on my page using vanilla javascript. I can't find the solution in the FB documentation and there aren't any tutorials on the Google FB.

Any help is much appreciated. Thanks, All

• javascript
• firebase
• firebase-realtime-database

Share Improve this question Follow edited Jul 14, 2016 at 14:53 Frank van Puffelen 600k8585 gold badges890890 silver badges860860 bronze badges asked Jul 14, 2016 at 4:49 Moe-JoeMoe-Joe 1,03033 gold badges1515 silver badges3030 bronze badges

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1 Answer 1

Sorted by: Reset to default 9

As the name implies dbRef is a reference to the data, it is not the data itself.

When you attach a listener to the reference with on(), you will get a snapshot of the data at that location. You can get the value from this snapshot and print it:

var dbRef = firebase.database().ref().child('jumbotron/header');
dbRef.on('value', snapshot => {
  console.log(snapshot.val());
});

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