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I have below function for fibonacci which is returning expected output

q)fib:{{x,sum -2#x}/[{last[x] < 100};x]}    
q)fib 1 1
1 1 2 3 5 8 13 21 34 55 89 144

How could we replace the value 100 in the inner function {last[x] < 100} with an argument from the outer function?

Expected function call structure -

q)fib[1 1;100]
1 1 2 3 5 8 13 21 34 55 89 144 /- expected output

I have below function for fibonacci which is returning expected output

q)fib:{{x,sum -2#x}/[{last[x] < 100};x]}    
q)fib 1 1
1 1 2 3 5 8 13 21 34 55 89 144

How could we replace the value 100 in the inner function {last[x] < 100} with an argument from the outer function?

Expected function call structure -

q)fib[1 1;100]
1 1 2 3 5 8 13 21 34 55 89 144 /- expected output

• kdb+

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2 Answers 2

Sorted by: Reset to default 2

Here's one way

q)fib:{{x,sum -2#x}/[{last[y]<x}y;x]}
q)fib[1 1;100]
1 1 2 3 5 8 13 21 34 55 89 144

You can also drop the inner lambdas and use compositions:

q)fib:{{x,sum -2#x}/[y>last@;x]}
q)fib[1 1;100]
1 1 2 3 5 8 13 21 34 55 89 144
q)
q)fib:{(y>last@){x,sum -2#x}/x}
q)fib[1 1;100]
1 1 2 3 5 8 13 21 34 55 89 144

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