php - XMLHttprequest sends an empty post - Stack Overflow

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I'm using the following code to send a request:

var ajaxHandler = new XMLHttpRequest();

ajaxHandler.onreadystatechange = function()
{
   if(ajaxHandler.readyState == 4)
   {
      console.log(ajaxHandler.responseText);
   }
}

ajaxHandler.open("POST", "filterCards", true);
ajaxHandler.send("category="+category+"&tag="+tag);

On the PHP side, I have this:

var_dump($_POST);

However, even though both the variables of category and tag have values, the console logs an empty array. What am I doing wrong with the post?

I'm using the following code to send a request:

var ajaxHandler = new XMLHttpRequest();

ajaxHandler.onreadystatechange = function()
{
   if(ajaxHandler.readyState == 4)
   {
      console.log(ajaxHandler.responseText);
   }
}

ajaxHandler.open("POST", "filterCards", true);
ajaxHandler.send("category="+category+"&tag="+tag);

On the PHP side, I have this:

var_dump($_POST);

However, even though both the variables of category and tag have values, the console logs an empty array. What am I doing wrong with the post?

• php
• javascript
• ajax
• xmlhttprequest

Share Improve this question Follow asked Apr 19, 2012 at 5:07 FibericonFibericon 5,8031313 gold badges3939 silver badges6565 bronze badges

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2 Answers 2

Sorted by: Reset to default 6

Add setRequestHeader before your send call:

ajaxHandler.setRequestHeader("Content-type","application/x-www-form-urlencoded");
ajaxHandler.send("category="+category+"&tag="+tag);

Replace:

   if(ajaxHandler.readyState == 4)
   {
      console.log(ajaxHandler.responseText);
   }

with

   if(ajaxHandler.readyState == 4 && ajaxHandler.status==200)
   {
      console.log(ajaxHandler.responseText);
   }

Hope this helps.

The answer by web-nomad is correct, but if you are still receiving an empty array, recall whether you are hiding file extensions in your server configuration. If you are, then a request to "file.extension" will be redirected to "file", and the POST data is lost.

This is a small error to make, but also easy to overlook. It is easy to assume the error is in the code rather than in the URL, particularly as the array is returned at all - so one might think the URL is correct.

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