javascript - Filter array if element is present in another array based on value - Stack Overflow

admin管理员组

文章数量:1356830

I have an object array like this:

var objectArray = [{id_5:"100"},
                   {id_1:"300"},
                   {id_2:"500"},
                   {id_4:"700"},
                   {id_3:"200"}];

And a normal array like this:

var normalArray = ["id_2","id_5","id_4"];

I want to subtract every element from the objectArray if there's a matching ID in the normalArray. I then want to order the newly created array by the object's value (lowest value being first).

So for the above example the result would be:

var newObjectArray = [{id_3:"200"},
                      {id_1:"300"}];

Is it possible to do this without jQuery?

I've seen similar questions like this one: Removing object from one array if present in another array based on value but I haven't been able to find an answer that works. Is it possible to do a pare and remove like this while still keeping the key:value pairs intact? Thanks in advance for any help with this!

I have an object array like this:

var objectArray = [{id_5:"100"},
                   {id_1:"300"},
                   {id_2:"500"},
                   {id_4:"700"},
                   {id_3:"200"}];

And a normal array like this:

var normalArray = ["id_2","id_5","id_4"];

I want to subtract every element from the objectArray if there's a matching ID in the normalArray. I then want to order the newly created array by the object's value (lowest value being first).

So for the above example the result would be:

var newObjectArray = [{id_3:"200"},
                      {id_1:"300"}];

Is it possible to do this without jQuery?

I've seen similar questions like this one: Removing object from one array if present in another array based on value but I haven't been able to find an answer that works. Is it possible to do a pare and remove like this while still keeping the key:value pairs intact? Thanks in advance for any help with this!

• javascript
• arrays

Share Improve this question Follow edited May 23, 2017 at 12:34 CommunityBot 111 silver badge asked Feb 17, 2017 at 11:56 EmilyEmily 1,15155 gold badges2121 silver badges4444 bronze badges 2

• 3 Everything is possible in JS without jQuery, since jQuery is written in JS. – Mitya Commented Feb 17, 2017 at 11:57
• @Emily,it worked my solution for you ? – Mihai Alexandru-Ionut Commented Feb 17, 2017 at 15:45

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 5

You should use filter method, which accepts as parameter a callback function.

Also, you have to use Object.keys() method in order to get the key of each object in objectArray.

To check if an element from objectArray doesn't appear in objectArray, you should use indexOf() method.

To achieve the sorted array, you have to use sort() method.

var objectArray = [{id_5:"100"},
                   {id_1:"300"},
                   {id_2:"500"},
                   {id_4:"700"},
                   {id_3:"200"}];

var normalArray = ["id_2","id_5","id_4"];
var newArray=objectArray.filter(function(item){
    return normalArray.indexOf(Object.keys(item)[0]) == -1;
}).sort(function(a,b){
    return a[Object.keys(a)[0]] - b[Object.keys(b)[0]];
});
console.log(newArray);

You can first use filter() to remove object with key from other array and then sort to sort result array by objects value.

var objectArray = [{id_5:"100"},{id_1:"300"},{id_2:"500"},{id_4:"700"},{id_3:"200"}];
var normalArray = ["id_2","id_5","id_4"];

var newArray = objectArray
  .filter(e => !normalArray.includes(Object.keys(e)[0]))
  .sort((a, b) => a[Object.keys(a)[0]] - b[Object.keys(b)[0]])
  
console.log(newArray)

本文标签： javascriptFilter array if element is present in another array based on valueStack Overflow