javascript - How to toggle elements in and out of DOM using jQuery detach() method? - Stack Overflow

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I have a group of divs arranged in a grid.

To style each div I'm selecting them with the nth-child() pseudo-class.

div.tile:nth-child(4n-7) .text { background-color: yellow; }

A user can hide divs by clicking on a button (which fires a jQuery function that adds a display: none rule to the class attribute in the selected div).

jQuery

$('.hide-divs').click(function () {
     $('.dolphin').toggleClass('hidden');
    })

CSS

.hidden { display: none; }

Here's the problem:

Even though display: none removes the div from the screen, it doesn't remove the div from the DOM, so the nth-child selector still counts it when applying styles, which in turn messes up the visual design of the grid.

The above layout is broken because only the first column should be yellow.

So my first thought was to use the jQuery remove() method, which takes elements (and its descendants) out of the DOM.

Turns out, however, once remove() is applied you can't get those divs back. They're gone. So the toggle function breaks.

After a bit of research I discovered the jQuery detach() method, which does the same thing as .remove(), except it stores the removed elements' data for later use.

From the jQuery website:

The .detach() method is the same as .remove(), except that .detach() keeps all jQuery data associated with the removed elements. This method is useful when removed elements are to be reinserted into the DOM at a later time.

Everything looks good for detach() to work with the toggle switch, except my efforts to implement it aren't working.

I've used the example on the jQuery website as a guide but it doesn't work on the grid. I also read various related posts on this site, but to no avail. I must be missing something.

Any feedback would be much appreciated.

/

$('.hide-divs').click(function() {
  $('.dolphin').toggleClass('hidden');
})

.row {
  display: flex;
  flex-wrap: wrap;
  width: 500px;
  padding: 0;
  margin: 0;
}
.text {
  height: 50px;
  width: 100px;
  margin: 10px;
  padding-top: 15px;
  background: tomato;
  color: #fff;
  text-align: center;
  font-size: 2em;
}
.tile:nth-child(4n-7) .text {
  border: 2px solid #ccc;
  background-color: yellow;
  color: #000;
}
button {
  padding: 10px;
  background-color: lightblue;
  position: relative;
  left: 200px;
}
.hidden {
  display: none;
}

<script src=".1.1/jquery.min.js"></script>
<div class="container">

  <div class="row">

    <div class="tile">
      <div class="text">01</div>
    </div>

    <div class="tile">
      <div class="text">02</div>
    </div>

    <div class="tile">
      <div class="text dolphin">03</div>
    </div>

    <div class="tile">
      <div class="text">04</div>
    </div>

    <div class="tile">
      <div class="text">05</div>
    </div>

    <div class="tile">
      <div class="text dolphin">06</div>
    </div>

    <div class="tile">
      <div class="text">07</div>
    </div>

    <div class="tile">
      <div class="text dolphin">08</div>
    </div>

    <div class="tile">
      <div class="text">09</div>
    </div>

    <div class="tile">
      <div class="text">10</div>
    </div>

    <div class="tile">
      <div class="text">11</div>
    </div>

    <div class="tile">
      <div class="text">12</div>
    </div>

  </div><!-- end .row -->

  <button type="button" class="hide-divs">HIDE DIVS 3, 6 &amp; 8</button>

I have a group of divs arranged in a grid.

To style each div I'm selecting them with the nth-child() pseudo-class.

div.tile:nth-child(4n-7) .text { background-color: yellow; }

A user can hide divs by clicking on a button (which fires a jQuery function that adds a display: none rule to the class attribute in the selected div).

jQuery

$('.hide-divs').click(function () {
     $('.dolphin').toggleClass('hidden');
    })

CSS

.hidden { display: none; }

Here's the problem:

Even though display: none removes the div from the screen, it doesn't remove the div from the DOM, so the nth-child selector still counts it when applying styles, which in turn messes up the visual design of the grid.

The above layout is broken because only the first column should be yellow.

So my first thought was to use the jQuery remove() method, which takes elements (and its descendants) out of the DOM.

Turns out, however, once remove() is applied you can't get those divs back. They're gone. So the toggle function breaks.

After a bit of research I discovered the jQuery detach() method, which does the same thing as .remove(), except it stores the removed elements' data for later use.

From the jQuery website:

The .detach() method is the same as .remove(), except that .detach() keeps all jQuery data associated with the removed elements. This method is useful when removed elements are to be reinserted into the DOM at a later time.

Everything looks good for detach() to work with the toggle switch, except my efforts to implement it aren't working.

I've used the example on the jQuery website as a guide but it doesn't work on the grid. I also read various related posts on this site, but to no avail. I must be missing something.

Any feedback would be much appreciated.

http://jsfiddle/tfyfpbb2/

$('.hide-divs').click(function() {
  $('.dolphin').toggleClass('hidden');
})

.row {
  display: flex;
  flex-wrap: wrap;
  width: 500px;
  padding: 0;
  margin: 0;
}
.text {
  height: 50px;
  width: 100px;
  margin: 10px;
  padding-top: 15px;
  background: tomato;
  color: #fff;
  text-align: center;
  font-size: 2em;
}
.tile:nth-child(4n-7) .text {
  border: 2px solid #ccc;
  background-color: yellow;
  color: #000;
}
button {
  padding: 10px;
  background-color: lightblue;
  position: relative;
  left: 200px;
}
.hidden {
  display: none;
}

<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">

  <div class="row">

    <div class="tile">
      <div class="text">01</div>
    </div>

    <div class="tile">
      <div class="text">02</div>
    </div>

    <div class="tile">
      <div class="text dolphin">03</div>
    </div>

    <div class="tile">
      <div class="text">04</div>
    </div>

    <div class="tile">
      <div class="text">05</div>
    </div>

    <div class="tile">
      <div class="text dolphin">06</div>
    </div>

    <div class="tile">
      <div class="text">07</div>
    </div>

    <div class="tile">
      <div class="text dolphin">08</div>
    </div>

    <div class="tile">
      <div class="text">09</div>
    </div>

    <div class="tile">
      <div class="text">10</div>
    </div>

    <div class="tile">
      <div class="text">11</div>
    </div>

    <div class="tile">
      <div class="text">12</div>
    </div>

  </div><!-- end .row -->

  <button type="button" class="hide-divs">HIDE DIVS 3, 6 &amp; 8</button>

• javascript
• jquery
• html
• css

Share Improve this question Follow edited Sep 8, 2016 at 16:04 Michael Benjamin asked Sep 3, 2015 at 21:34 Michael BenjaminMichael Benjamin 373k110110 gold badges613613 silver badges730730 bronze badges 0

Add a ment  | 

4 Answers 4

Sorted by: Reset to default 7

I suggest still using detach. You can do so with this code:

var divs;

$('.hide-divs').on('click', function () {
    if(divs) {
        $(divs).appendTo('.row');
        divs = null;
    } else {
        divs = $('.dolphin').parent().detach();
    }
});

Then to ensure that the same order is used, I came up with this bit of code:

$('.tile').each(function(i){
    $(this).data('initial-index', i);
});

...

$(divs).each(function(){
    var oldIndex = $(this).data('initial-index');
    $('.tile').eq(oldIndex).before(this);
});

Put it all together and we get this code:

var divs;

$('.tile').each(function(i){
    $(this).data('initial-index', i);
});

$('.hide-divs').on('click', function () {
    if(divs) {
        $(divs).appendTo('.row').each(function(){
            var oldIndex = $(this).data('initial-index');
            $('.tile').eq(oldIndex).before(this);
        });
        divs = null;
    } else {
        divs = $('.dolphin').parent().detach();
    }
});

Demo on jsfiddle: http://jsfiddle/tqbzff2v/2/

Everyone was close, but here is exactly what you are looking for with your current html markup: http://jsfiddle/vs5o5nLb/2/

The trick is setting yourself up ahead of time with what you need to actually toggle, then keeping that information around to insert and detach from.

var $els = $( '.tile' );
var stack = [];
var isShown = true;

$els.each(function() {
    var $this = $( this );
    if ( $this.find('.dolphin').length ) {
        stack.push({
            $el : $this,
            index : $els.index( this )
        });
    }
});

$('.hide-divs').click(function () {
    if ( isShown ) {
        $.each(stack, function() {
            this.$el.detach();
        });
        isShown = false;
    } else {
        $.each(stack, function() {
            $('.tile').eq( this.index ).before( this.$el );
        });
        isShown = true;
    }
});

I hope it helps.

I have used remove() with toggle to remove and delete elements. example: each time on mouse hover and check if text is printed in unordered list and then elements are removed on the next click. Jquery

        $('h1').hover(function(){
                //alert('test toggle');
               remove_el();
               for(var i=0;i<5;i++){ 
               $('ul').append('<li>'+'END_check else'+i+'</li>').toggle();

                 }
               }

                );

            function remove_el(){

                $('li').remove();
            };

I'm not very sure if this what you'd like to do - http://jsfiddle/tfyfpbb2/1/

If so, you just need to add three row classes instead of one. This way each row has it's own "space" and will not miss up the next row's styling.

<div class="row">
    <div class="tile">
        <div class="text">01</div>
    </div>

    <div class="tile">
        <div class="text">02</div>
    </div>

    <div class="tile">
        <div class="text dolphin">03</div>
    </div>

    <div class="tile">
        <div class="text">04</div>
    </div>
</div> 

Hope that helps! Let me know if that's not what you wanted and I can edit my answer.

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