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I am getting value from a text field. I want to show an alert message if a special character, say % doesn't appear at the end of entered input.

Usecases:

1. ab%C - show alert
2. %abc- show alert
3. a%bc- show alert
4. abc%- ok

The regex i came up so far is this.

var txtVal = document.getElementById("sometextField").value;

if (!/^[%]/.test(txtVal))
   alert("% only allowed at the end.");

Please help. Thanks

I am getting value from a text field. I want to show an alert message if a special character, say % doesn't appear at the end of entered input.

Usecases:

1. ab%C - show alert
2. %abc- show alert
3. a%bc- show alert
4. abc%- ok

The regex i came up so far is this.

var txtVal = document.getElementById("sometextField").value;

if (!/^[%]/.test(txtVal))
   alert("% only allowed at the end.");

Please help. Thanks

• javascript
• regex
• string

Share Improve this question Follow edited Jan 2, 2012 at 1:44 Nomad asked Jan 2, 2012 at 1:43 NomadNomad 1,1001212 gold badges2929 silver badges4242 bronze badges 3

• What if % is not present in the string? – Sergio Tulentsev Commented Jan 2, 2012 at 1:45
• @Sergio Tulentsev. The string wont have it. It's user entered value which will contain the %, meaning user will enter it abcde%f etc. – Nomad Commented Jan 2, 2012 at 1:47
• are you saying that we can assume that '%' always exists in the string, and we should check if it's the last symbol or not? – Sergio Tulentsev Commented Jan 2, 2012 at 1:49

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4 Answers 4

Sorted by: Reset to default 5

No need for a regex. indexOf will find the first occurrence of a character, so just check it it's at the end:

if(str.indexOf('%') != str.length -1) {
  // alert something
}

2020 edit, use string.endsWith()

You don't need regex to check for this at all.

var foo = "abcd%ef";
var lastchar = foo[foo.length - 1];
if (lastchar != '%') {
    alert("hello");
}

http://jsfiddle/cwu4S/

if (/%(?!$)/.test(txtVal))
  alert("% only allowed at the end.");

or to make it more readable by not using a RegExp:

var pct = txtVal.indexOf('%');
if (0 <= pct && pct < txtVal.length - 1) {
  alert("% only allowed at the end.");
}

Would this work?

if (txtVal[txtVal.length-1]=='%') {
    alert("It's there");
}
else {
    alert("It's not there");
}

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