admin管理员组文章数量:1353103
I found two similar answers here but both were unsuccessful for my situation (given my limited ability to translate them to my situation). I have a page with a lot of fairly large images and the default method of Bootstrap is to load all the modal images upon page load. The visible html renders fairly quickly (I have a spinner for that) but the additional load time for the hidden modals makes the page impractical. I want the page to load only the visible (non-modal) content to plete the page load (and clear the spinner) and then load each modal's content only when that modal is fired. I've tried every lazyload solution I could find but the images will not render in the modal (the 'data-src' placeholders render but not the 'src' images that are supposed to replace them). I only want to lazyload (or load on 'show.bs.modal') the large images of the modal, those within the 'modal-body' class. I hope this is clear enough.
Sample code:
/* Javascript placed in the head */
<script>
function lazyLoad(){
var $images = $('.lazy_load');
$images.each(function(){
var $img = $(this),
src = $img.attr('data-src');
$img
.on('load',imgLoaded($img[0]))
.attr('src',src);
});
};
$('.modal-body').on("show.bs.modal", function () {
lazyLoad();
};
</script>
/* HTML in the modal section */
<div class="portfolio-modal modal fade" id="portfolioModal1" tabindex="-1" role="dialog" aria-hidden="true">
<div class="modal-content">
<div class="galleryheader">
<img src="headerimage_1.png" height="77" width="1024">
</div>
<div class="close-modal" data-dismiss="modal">
<div class="lr">
<div class="rl">
</div>
</div>
</div>
<div class="container">
<div class="row">
<div>
<div class="modal-body lazy_load">
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" data-src="images/largeimage_1A.jpg" height="585" width="800"class="img-centered" alt=""/>
</div>
<div class="modal-body lazy_load">
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" data-src="images/largeimage_1A.jpg" height="585" width="800"class="img-centered" alt=""/>
</div>
<div class="modal-body lazy_load">
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" data-src="images/largeimage_1A.jpg" height="585" width="800"class="img-centered" alt=""/>
</div>
</div>
</div>
</div>
<div class="close-lower" data-dismiss="modal">
<IMG SRC="images/close.jpg" WIDTH="85" HEIGHT="32"></a>
</div>
</div>
</div>
</div>
I found two similar answers here but both were unsuccessful for my situation (given my limited ability to translate them to my situation). I have a page with a lot of fairly large images and the default method of Bootstrap is to load all the modal images upon page load. The visible html renders fairly quickly (I have a spinner for that) but the additional load time for the hidden modals makes the page impractical. I want the page to load only the visible (non-modal) content to plete the page load (and clear the spinner) and then load each modal's content only when that modal is fired. I've tried every lazyload solution I could find but the images will not render in the modal (the 'data-src' placeholders render but not the 'src' images that are supposed to replace them). I only want to lazyload (or load on 'show.bs.modal') the large images of the modal, those within the 'modal-body' class. I hope this is clear enough.
Sample code:
/* Javascript placed in the head */
<script>
function lazyLoad(){
var $images = $('.lazy_load');
$images.each(function(){
var $img = $(this),
src = $img.attr('data-src');
$img
.on('load',imgLoaded($img[0]))
.attr('src',src);
});
};
$('.modal-body').on("show.bs.modal", function () {
lazyLoad();
};
</script>
/* HTML in the modal section */
<div class="portfolio-modal modal fade" id="portfolioModal1" tabindex="-1" role="dialog" aria-hidden="true">
<div class="modal-content">
<div class="galleryheader">
<img src="headerimage_1.png" height="77" width="1024">
</div>
<div class="close-modal" data-dismiss="modal">
<div class="lr">
<div class="rl">
</div>
</div>
</div>
<div class="container">
<div class="row">
<div>
<div class="modal-body lazy_load">
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" data-src="images/largeimage_1A.jpg" height="585" width="800"class="img-centered" alt=""/>
</div>
<div class="modal-body lazy_load">
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" data-src="images/largeimage_1A.jpg" height="585" width="800"class="img-centered" alt=""/>
</div>
<div class="modal-body lazy_load">
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" data-src="images/largeimage_1A.jpg" height="585" width="800"class="img-centered" alt=""/>
</div>
</div>
</div>
</div>
<div class="close-lower" data-dismiss="modal">
<IMG SRC="images/close.jpg" WIDTH="85" HEIGHT="32"></a>
</div>
</div>
</div>
</div>
Share
Improve this question
asked Oct 6, 2016 at 0:23
evanonearthevanonearth
1031 silver badge6 bronze badges
0
1 Answer
Reset to default 7Firstly, put the lazy_load
class on the img
element, not on the parent div
. Secondly the jQuery you need is something like this:
$('.portfolio-modal').on("show.bs.modal", function () {
$('.lazy_load').each(function(){
var img = $(this);
img.attr('src', img.data('src'));
});
});
Notes:
- Use the
portfolio-modal
class to identify the modal. - Use the jQuery
data()
method to get the image to lazily load.
本文标签: javascriptLazy Load Images Only After Bootstrap Modal has OpenedStack Overflow
版权声明:本文标题:javascript - Lazy Load Images Only After Bootstrap Modal has Opened - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1743874127a2554014.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论