javascript - Sort array of strings with negative and positive numbers - Stack Overflow

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Firstly I could not find a question addressing the whole issue.

I used to pare arrays like this:

array.sort((a, b) => {
    return a.localeCompare(b, undefined, {numeric: true, sensitivity: 'base'})
})

But I realized it does not work on an array like ['a', 'A', 'B', -1.50', '0', '1.50', '-2', '2'].

The expected output would be: ['-2', '-1.50', '0', '1.50', '2', 'A', 'a', 'B'].

I have some dirty ideas to achieve it. But maybe there is a clean and easy way.

Firstly I could not find a question addressing the whole issue.

I used to pare arrays like this:

array.sort((a, b) => {
    return a.localeCompare(b, undefined, {numeric: true, sensitivity: 'base'})
})

But I realized it does not work on an array like ['a', 'A', 'B', -1.50', '0', '1.50', '-2', '2'].

The expected output would be: ['-2', '-1.50', '0', '1.50', '2', 'A', 'a', 'B'].

I have some dirty ideas to achieve it. But maybe there is a clean and easy way.

• javascript

Share Improve this question Follow edited May 9, 2018 at 11:40 Ali Ankarali asked May 9, 2018 at 7:37 Ali AnkaraliAli Ankarali 3,13733 gold badges2121 silver badges3232 bronze badges 5

• 2 I'm not sure, what is the field argument intended to do? – CertainPerformance Commented May 9, 2018 at 7:40
• Given an array of objects, I parameterized the attribute of the object, so that I won't write a sort method for different attributes. – Ali Ankarali Commented May 9, 2018 at 7:42
• I guess it is not much relevant to the question so removed it to avoid confusion. – Ali Ankarali Commented May 9, 2018 at 7:44
• why do you need {numeric: true, sensitivity: 'base'}? – Nina Scholz Commented May 9, 2018 at 7:45
• @NinaScholz stackoverflow./a/38641281/6469020 – Ali Ankarali Commented May 9, 2018 at 7:46

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 7

You could prepend the parison by taking the delta of the wanted properties. This saves the order for numerical values.

console.log(
    ['a', 'A', 'B', '-1.50', '0', '1.50', '-2', '2', 'D']
        .sort((a, b) => a - b || a.localeCompare(b, undefined, {sensitivity: 'base'}))
);

numeric: true option can be omitted for there won't be two numbers to pare at the left hand side of the expression.

const customSort = (array) => {
    return array.sort((a, b) => {

        let r = /^-?\d+(?:\.\d+)?$/;

        if (r.test(a) && r.test(b))
        {
            return a - b;
        }

        return a.localeCompare(b, undefined, {numeric: true, sensitivity: 'base'})
    })
}

console.log(customSort(['a', 'A', 'B', '-1.50', '0', '1.50', '-2', '2']));
// => [ '-2', '-1.50', '0', '1.50', '2', 'a', 'A', 'B' ]

You should use isNaN method in order to check if you pare numerical strings. If yes, localeCompare is not remended , you need to use Number(a) - Number(b)

array = ['a', 'A', 'B','-1.50', '0', '1.50', '-2', '2']
array.sort((a, b) => {
  return !isNaN(a) && !isNaN(b) ? Number(a)-Number(b) : a.localeCompare(b, undefined, { sensitivity: 'base'});
})
    
console.log(array);

Since in Javascript the - operator is defined only for numeric subtraction, the operands will be coerced to Number. So you could simply use:

array.sort((a, b) => {
  return a - b || a.localeCompare(b, undefined, { sensitivity: 'base'});
})

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