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Well i have this ajax code which will return the result from MySql in Success block.

$.ajax({
   type:"POST",
   url:"index.php",
   success: function(data){
            alert(data);                
        }
});

My Query

$sql = "SELECT * FROM tablename";
$rs=parent::_executeQuery($sql);
$rs=parent::getAll($rs);
print_r($rs);
return $rs

My Response Array in alert of Success AJAX

Array
(
    [0] => Array
        (
            [section_id] => 5
            [version] => 1
            [section_name] => Crop Details
            [id] => 5
            [document_name] => Site Survey
            [document_master_id] => 1
            [document_section_id] => 5
        )

    [1] => Array
        (           
            [section_id] => 28
            [version] => 1
            [section_name] => Vegetative Report           
            [id] => 6
            [document_name] => Site Survey
            [document_master_id] => 1
            [document_section_id] => 28
        )

)

I want to get only section_name and document_name from the result so that i can append these two values to my list.

Well i have this ajax code which will return the result from MySql in Success block.

$.ajax({
   type:"POST",
   url:"index.php",
   success: function(data){
            alert(data);                
        }
});

My Query

$sql = "SELECT * FROM tablename";
$rs=parent::_executeQuery($sql);
$rs=parent::getAll($rs);
print_r($rs);
return $rs

My Response Array in alert of Success AJAX

Array
(
    [0] => Array
        (
            [section_id] => 5
            [version] => 1
            [section_name] => Crop Details
            [id] => 5
            [document_name] => Site Survey
            [document_master_id] => 1
            [document_section_id] => 5
        )

    [1] => Array
        (           
            [section_id] => 28
            [version] => 1
            [section_name] => Vegetative Report           
            [id] => 6
            [document_name] => Site Survey
            [document_master_id] => 1
            [document_section_id] => 28
        )

)

I want to get only section_name and document_name from the result so that i can append these two values to my list.

• javascript
• php
• jquery
• mysql
• ajax

Share Improve this question Follow asked Dec 15, 2014 at 6:56 MatarishvanMatarishvan 2,43233 gold badges4242 silver badges7171 bronze badges 1

• 1 Use json_encode() to return the response as JSON, so can parse it in Javascript. – Barmar Commented Dec 15, 2014 at 6:58

Add a ment  | 

4 Answers 4

Sorted by: Reset to default 3

Don't return the response using print_r(), use json_encode():

echo json_encode($rs);

Then in the Javascript, you can do:

$.ajax({
   type:"POST",
   url:"index.php",
   dataType: 'json'
   success: function(data){
        for (var i = 0; i < data.length; i++) {
            console.log(data[i].section_name, data[i].document_name);          
        }
    }
});

change your select query with

$sql = "SELECT section_name,document_name FROM tablename";

$sql = "SELECT * FROM tablename";
$rs=parent::_executeQuery($sql);
$rs=parent::getAll($rs);

return json_encode($rs);

index.php

$.ajax({
   type:"POST",
   url:"index.php",
   success: function(data){
        alert(data);
        var data = JSON.parse(data);
        /* you can use $.each() function here  */                
    }
});

Do this:

$sql = "SELECT * FROM tablename";
$rs=parent::_executeQuery($sql);
$rs=parent::getAll($rs);
$resp = array();
foreach( $rs as $each ){
    $resp[]['section_name'] = $each['section_name'];
    $resp[]['document_name'] = $each['document_name'];
}
return json_encode($resp);

Access JSON response like this:

for (var i = 0; i < data.length; i++) {
    console.log(data[i].section_name, data[i].document_name);          
}

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