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I have a function that returns 5 objects, and I would like to declare 4 of them using const and 1 of them using let. If I wanted all objects declared using const I could do:

const { thing1, thing2, thing3, thing4, thing5 } = yield getResults();

My current workaround is:

const results = yield getResults();

const thing1 = results.thing1;
const thing2 = results.thing2;
const thing3 = results.thing3;
const thing4 = results.thing4;

let thing5 = results.thing5; 

But I'm wondering if destructuring assignment allows you to do this more elegantly.

No mention of this question on MDN or on stackoverflow, as far as I can see.

I have a function that returns 5 objects, and I would like to declare 4 of them using const and 1 of them using let. If I wanted all objects declared using const I could do:

const { thing1, thing2, thing3, thing4, thing5 } = yield getResults();

My current workaround is:

const results = yield getResults();

const thing1 = results.thing1;
const thing2 = results.thing2;
const thing3 = results.thing3;
const thing4 = results.thing4;

let thing5 = results.thing5; 

But I'm wondering if destructuring assignment allows you to do this more elegantly.

No mention of this question on MDN or on stackoverflow, as far as I can see.

• javascript
• ecmascript-6

Share Improve this question Follow asked Jun 20, 2016 at 22:03 the hollathe holla 8161111 silver badges1717 bronze badges 1

• 3 Well just do const {thing1, …} = results; let {thing5} = results;? – Bergi Commented Jun 20, 2016 at 22:15

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 8

It isn't possible to perform a destructure that initialises both let and const variables simultaneously. However the assignments to const can be reduced to another destructure:

const results = yield getResults()

const { thing1, thing2, thing3, thing4 } = results

let thing5 = results.thing5

You still can use destructuring separately:

const results = yield getResults();
const { thing1, thing2, thing3, thing4} = results;
let   { thing5 } = results;

Alternatively, it is possible to do

let thing5;
const { thing1, thing2, thing3, thing4 } = { thing5 } = yield getResults();

but I guess that should rather be avoided to reduce the WTF/minute of your code.

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