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I am clueless about regular expressions, but I know that they're the right tool for what I'm trying to do here: I'm trying to extract a numerical value from a string like this one:
approval=not requested^assignment_group=12345678901234567890123456789012^category=Test^contact_type=phone^
Ideally, I'd extract the following from it: 12345678901234567890123456789012
None of the regexes I've tried have worked. How can I get the value I want from this string?
I am clueless about regular expressions, but I know that they're the right tool for what I'm trying to do here: I'm trying to extract a numerical value from a string like this one:
approval=not requested^assignment_group=12345678901234567890123456789012^category=Test^contact_type=phone^
Ideally, I'd extract the following from it: 12345678901234567890123456789012
None of the regexes I've tried have worked. How can I get the value I want from this string?
- 2 What is the regex you've tried? – gen_Eric Commented Jul 9, 2012 at 14:44
- 1 Is it the only number you'll ever have? – Madara's Ghost Commented Jul 9, 2012 at 14:44
4 Answers
Reset to default 7This will get all the numbers:
var myValue = /\d+/.exec(myString)
mystr.match(/assignment_group=([^\^]+)/)[1]; //=> "12345678901234567890123456789012"
This will find everything from the end of "assignment_group=" up to the next caret ^
symbol.
Try something like this:
/\^assignment_group=(\d*)\^/
This will get the number for assignment_group
.
var str = 'approval=not requested^assignment_group=12345678901234567890123456789012^category=Test^contact_type=phone^',
regex = /\^assignment_group=(\d*)\^/,
matches = str.match(regex),
id = matches !== null ? matches[1] : '';
console.log(id);
If there is no chance of there being numbers anywhere but when you need them, you could just do:
\d+
the \d matches digits, and the + says "match any number of whatever this follows"
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