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I have a jqGrid column which name may change (is a variable), how do I get the name and hide it?

Something along the lines of the below (which don't work)

 $('#tblGridName').jqGrid('hideCol',4);

or

var infoName = $('.ui-jqgrid-htable th:eq(4)').text();
$('#tblGridName').jqGrid('hideCol',infoName );

I have a jqGrid column which name may change (is a variable), how do I get the name and hide it?

Something along the lines of the below (which don't work)

 $('#tblGridName').jqGrid('hideCol',4);

or

var infoName = $('.ui-jqgrid-htable th:eq(4)').text();
$('#tblGridName').jqGrid('hideCol',infoName );

• javascript
• jquery
• jqgrid
• hide

Share Improve this question Follow asked Aug 1, 2010 at 23:03 bcmbcm 5,5001010 gold badges6060 silver badges9292 bronze badges

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2 Answers 2

Sorted by: Reset to default 8

You can just use

var cm = myGrid.getGridParam("colModel");

to get the current colModel. Then cm[4].name is the name of the column. So

var colPos = 4;
var myGrid = $('#tblGridName');
myGrid.jqGrid('hideCol', myGrid.getGridParam("colModel")[colPos].name);

do what you need.

Sorry, found the answer almost right off.

Just amended this

var infoName = $('.ui-jqgrid-htable th:eq(4)').text();
$('#tblGridName').jqGrid('hideCol',infoName );

to be

var infoName = $.trim( $('.ui-jqgrid-htable th:eq(4)').text() );
$('#tblGridName').jqGrid('hideCol',infoName );

Any better solutions weled.

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