admin管理员组文章数量:1340649
I am trying to find a model within a collection with an attribute equal to html select option value.
<div id="hospital-details">
<select name="hospitalnames">
<option><%- model.get('name') %></option>
</select>
</div>
whenever hospital name is changed, jquery change callback is triggered to find locationModel with selected option value as attribute value as shown below,
$('select[name="hospitalnames"]').change(function() {
var name = $(this).val();
locationListCollection.each(function(locationModel) {
if ($.trim(locationModel.get('name')) == $.trim(name)) {
that.locationModel = locationModel;
return false; // control is returned to underscore.min.js
}
});
});
console.log(that.locationModel); // this is not being displayed at all
After the locationModel with an attribute is found, I am unable to e out the loop. Any help ? At this moment I have looked into this but without success.
I am trying to find a model within a collection with an attribute equal to html select option value.
<div id="hospital-details">
<select name="hospitalnames">
<option><%- model.get('name') %></option>
</select>
</div>
whenever hospital name is changed, jquery change callback is triggered to find locationModel with selected option value as attribute value as shown below,
$('select[name="hospitalnames"]').change(function() {
var name = $(this).val();
locationListCollection.each(function(locationModel) {
if ($.trim(locationModel.get('name')) == $.trim(name)) {
that.locationModel = locationModel;
return false; // control is returned to underscore.min.js
}
});
});
console.log(that.locationModel); // this is not being displayed at all
After the locationModel with an attribute is found, I am unable to e out the loop. Any help ? At this moment I have looked into this but without success.
Share Improve this question edited May 23, 2017 at 11:47 CommunityBot 11 silver badge asked Oct 9, 2013 at 4:47 geekgugigeekgugi 3891 gold badge6 silver badges23 bronze badges4 Answers
Reset to default 9You're using the wrong method if you're searching for the first match. Collections have lots of Underscore methods mixed in, in particular they have find
mixed in:
find
_.find(list, iterator, [context])
Looks through each value in the list, returning the first one that passes a truth test (iterator), or
undefined
if no value passes the test.
Something like this:
var name = $.trim($(this).val());
that.locationModel = locationListCollection.find(function(locationModel) {
return $.trim(locationModel.get('name')) == name;
});
and if the name
s in your model are pre-trimmed and nice and clean, then you could use findWhere
:
findWhere
collection.findWhere(attributes)
Just like where, but directly returns only the first model in the collection that matches the passed attributes.
like this:
var name = $.trim($(this).val());
that.locationModel = locationListCollection.findWhere({ name: name });
BTW, this:
console.log(locationModel);
won't give you anything because locationModel
and that.locationModel
are different things.
You can always go oldschool.
$('select[name="hospitalnames"]').change(function() {
var name = $(this).val();
for (var i = 0; i < locationListCollection.length; ++i) {
var locationModel = locationListCollection.models[i];
if ($.trim(locationModel.get('name')) == $.trim(name)) {
that.locationModel = locationModel;
break;
}
}
});
Try this,
var name = $(this).val();
var flag=true;
locationListCollection.each(function(locationModel) {
if (flag && $.trim(locationModel.get('name')) == $.trim(name)) {
that.locationModel = locationModel;
flag=false;
//return false;// to break the $.each loop
}
});
The short is no.
If you take a look at underscore's source you'll see that they use a breaker object to quickly stop a .each() but that is only available internally.
I would not remend this but you could always modify the source to expose this breaker object (see baseline setup in the annotated source http://underscorejs/docs/underscore.html). Then you would just return this object instead of returning false. But you would probably need to remove the native forEach call to keep the behaviour consistent. So it's not worth it!
_.each(function(arr) {
if(condition) {
return _.breaker; // Assuming you changed the source.
}
});
Since you are searching for a single item instead of .each() use:
var locationModel = _.find(arr, function(item) {
return $.trim(locationModel.get('name')) == $.trim(name);
));
本文标签: javascriptbreaking out of an underscore eachStack Overflow
版权声明:本文标题:javascript - breaking out of an underscore each - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1743643103a2515050.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论